A 0.025-g sample of a compound composed of boron and hydrogen, with a molecular mass of ~28 amu, burns spontaneously when exposed to air, producing 0.063 g of B2O3. What are the empirical and molecular formulas of the compound?

Short Answer

Expert verified

Empirical formula = B1H3

Molecular formula = B2H6

Step by step solution

01

Information given

We can write the equation

Bx Hy + O2→B2O3 + H2O

0.025 g 0.063 g

0.063 g of B2O3 x 1 mol of B2O3 x 2 mol B x 10.81g of B

69.62g of B2O3 1 mol B2O3 1 mol B

= 0.01956 g of B

Bx Hy = 0.025 g

So g of H = 0.025 g – 0.01956 g = 0.00544 g of H

02

Required formula

% Grams \( \to \) mols \( \to \) mol ratio \( \to \) empirical formula \( \to \) molecular formula

0.01956 g of B x (1 mol B/10.81 g mol B) = (0.0081 mol B/0.0081) = 1 mol B

0.00544 g of H x (1 mol H/1g mol H) = (0.00540 mol H/0.0081) = 3 mol H

Empirical formula = B1H3

Molecular mass/ Empirical mass = 28/ 13.83 = 2

Molecular formula = B2H6

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following equations to answer the next four questions:

i.\({H_2}O\left( s \right) \to {H_2}O\left( l \right)\)

ii.\(N{a^ + }\left( {aq} \right) + C{l^ - }\left( {aq} \right) + A{g^ + }\left( {aq} \right) + NO_3^ - \left( {aq} \right) \to AgCl\left( s \right) + N{a^ + }\left( {aq} \right) + NO_3^ - \left( {aq} \right)\)

iii.\(C{H_3}OH\left( g \right) + {O_2}\left( g \right) \to C{O_2}\left( g \right) + {H_2}O\left( g \right)\)

iv. \(2{H_2}O\left( l \right) \to 2{H_2}\left( g \right) + {O_2}\left( g \right)\)

v. \({H^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right) \to {H_2}O\left( l \right)\)

(a) Which equation describes a physical change?

(b)Which equation identifies the reactants and products of a combustion reaction?

(c)Which equation is not balanced?

(d)Which is a net ionic equation?

Fill in the blank with a single chemical formula for a covalent compound that will balance the equation:

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen and water. (Hint Balance oxygen last, since it is present in more than one molecule on the right side of the equation)

What volume of 0.600 M HCl is required to react completely with 2.50 g of sodium hydrogen carbonate?

\({\rm{NaHC}}{{\rm{O}}_{3(aq)}}{\rm{ + HC}}{{\rm{l}}_{(aq)}}{\rm{ }} \to {\rm{ NaC}}{{\rm{l}}_{(aq)}}{\rm{ + C}}{{\rm{O}}_{2(aq)}}{\rm{ + }}{{\rm{H}}_2}{{\rm{O}}_{({\rm{l}})}}\)

Balance the following equations:

\(\begin{array}{l}\;(a)\;PC{l_5}\left( s \right) + {H_2}O\left( l \right) \to POC{l_3}\left( l \right) + HCl\left( {aq} \right)\\\left( b \right)\,Cu\left( s \right) + HN{O_3}\left( {aq} \right) \to Cu{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}O\left( l \right) + NO\left( g \right)\\\left( c \right){H_2}\left( g \right) + {I_2}\left( g \right) \to HI\left( s \right)\\\left( d \right)\,Fe\left( s \right) + {O_2}\left( g \right) \to F{e_2}{O_3}\left( s \right)\\\left( e \right)\,Na\left( s \right) + {H_2}O\left( l \right) \to NaOH\left( {aq} \right) + {H_2}\left( g \right)\\\left( f \right)\,{\left( {N{H_4}} \right)_2}C{r_2}{O_7}\left( s \right) \to C{r_2}{O_3}\left( s \right) + {N_2}\left( g \right) + {H_2}O\left( g \right)\\\left( g \right){P_4}\left( s \right) + C{l_2}\left( g \right) \to PC{l_3}\left( l \right)\\\left( h \right)PtC{l_4}\left( s \right) \to Pt\left( s \right) + C{l_2}\left( g \right)\end{array}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free