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Chapter 5: Q31E (page 270)

When 0.740g sample trinitrotoluene (TNT), C7H5N2O6, is burned in a bomb calorimeter, the temperature increases from 23.4˚C to 26.9˚C. The heat capacity of the calorimeter is 534J/˚C, and it contains 675ml of water. How much heat was produced by the combustion of TNT sample?

Short Answer

Expert verified

The heat of the combustion for this reaction is 1.18 × 104J.

Step by step solution

01

Given data

The mass of the TNT = 0.740 g

The increase in the temperature (∆T) = (26.9 – 23.4)˚C = 3.5˚C

The heat capacity of the calorimeter (C) = 534 J/˚C

02

Calculation of heat

The formula that is used in finding the heat of the combustion (q) in a bomb calorimeter is:

(qbomb) = C × ∆T, where the symbols have their usual meaning. = 534 J/˚C × 3.5˚C

= 1869 J

The formula that is used in finding the heat from water is (qwater) = ms∆T, where the symbols have their usual meaning.

qwater = 675 g × 4.184 J/g℃ × 3.5℃

= 9884.7 J

Therefore, the heat of the reaction (qreaction) = qbomb+ qwater

= 9884.7 J + 1869 J

= 1.18 × 104 J

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