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Chapter 5: Q40 E (page 271)

Using the data in the check your learning section of example 5.5, calculate ∆H in kJ/mol of AgNO3(aq) in the reaction :

NaCl(aq)+AgNO3(aq)→ AgCl(s)+NaNO3 (aq)

Short Answer

Expert verified

∆H in kJ/mol of AgNO3(aq) in the reaction :

NaCl(aq)+AgNO3(aq)→ AgCl(s)+NaNO3 (aq) is -67kJ/mol

Step by step solution

01

Given data

Data we are provided with:

100ml of 0.200M NaCl is mixed with 100ml of 0.200M AgNO3.

The heat of thereaction is, qreaction = -1.34k J.

02

Calculation of enthalpy change

The number of moles of NaCl = 0.200 × 0.1 L = 0.02 mol

The number of moles of AgNO3 = 0.200 × 0.1 L = 0.02 mol

Hence, ∆H = -67 kJ/mol.

Therefore, enthalpy change when 1 mol of AgNO3(aq) reacts is:

\begin{aligned}Enthalpychange=\frac{-1.34kJ}{0.02mol}=-67J/mol\end{aligned}

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