Indicate the coordination number for the central metal atom in each of the following coordination compounds:

\(\begin{aligned}{}(a)\left( {Pt{{\left( {{H_2}O} \right)}_2}B{r_2}} \right)\\(b)\left( {Pt\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\left( {py = } \right.pyridine,\left. {{C_5}{H_5}\;N} \right)\\(c)\left( {Zn{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\\(d)\left( {Zn\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\\(e)\left( {Ni{{\left( {{H_2}O} \right)}_4}C{l_2}} \right)\\(f){\left( {Fe{{(en)}_2}{{(CN)}_2}} \right)^ + }\left( {en = } \right.ethylenediamine,\left. {{C_2}{H_8}\;{N_2}} \right)\end{aligned}\)

Short Answer

Expert verified

The number of ligands attached to the central metal ion attached through the secondary valencies and are present inside the coordination sphere is said to be the coordination number of central metal ion.

Step by step solution

01

Given information

We are asked to indicate the coordination number for the central metal atom in each of the following coordination compounds of\(\begin{aligned}{}(a)\left( {Pt{{\left( {{H_2}O} \right)}_2}B{r_2}} \right)\\(b)\left( {Pt\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\left( {py = } \right.pyridine,\left. {{C_5}{H_5}\;N} \right)\\(c)\left( {Zn{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\\(d)\left( {Zn\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\\(e)\left( {Ni{{\left( {{H_2}O} \right)}_4}C{l_2}} \right)\\(f){\left( {Fe{{(en)}_2}{{(CN)}_2}} \right)^ + }\left( {en = } \right.ethylenediamine,\left. {{C_2}{H_8}\;{N_2}} \right)\end{aligned}\)

02

Explanation

\((a)\left( {Pt{{\left( {{H_2}O} \right)}_2}B{r_2}} \right)\)

  • In this,\({\bf{4}}\)monodentate ligands are present inside the coordination sphere, which clearly indicated that the coordination number of the central metal ion\({\bf{Pt}}\)is\({\bf{4}}\).

\((b)\left( {Pt\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\left( {py = } \right.pyridine,\left. {{C_5}{H_5}\;N} \right)\)

  • Here also, we could see\({\bf{4}}\)monodentate ligands present inside the coordination sphere, which clearly indicated that the coordination number of the central metal ion\({\bf{Pt}}\)is\({\bf{4}}\).

\((c)\left( {Zn{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\)

  • Here again, we could see\({\bf{4}}\)monodentate ligands present inside the coordination sphere, which clearly indicated that the coordination number of the central metal ion\(Zn\)is\({\bf{4}}\).

\((d)\left( {Zn\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\)

  • Here also, we could see\({\bf{4}}\)monodentate ligands present inside the coordination sphere, which clearly indicated that the coordination number of the central metal ion\(Zn\)is\({\bf{4}}\).

\((e)\left( {Ni{{\left( {{H_2}O} \right)}_4}C{l_2}} \right)\)

  • Here, We can see that\({\bf{6}}\)monodentate ligands are present inside the coordination sphere, which means the coordination number of the central metal ion\({\rm{Ni}}\)is\({\bf{6}}\).

\((f){\left( {Fe{{(en)}_2}{{(CN)}_2}} \right)^ + }\left( {en = } \right.ethylenediamine,\left. {{C_2}{H_8}\;{N_2}} \right)\)

  • We can see that\({\bf{2}}\)monodentate\(\left( {C{N^ - }} \right)\)ligands and\({\bf{2}}\)bidentate\((en)\)ligands are present inside the coordination sphere, which shows that the coordination number of the central metal ion\({\bf{Fe}}\)is\({\bf{6}}\).
  • Since\({\bf{2}}\)monodentate ligans donate\({\bf{2}}\)electrons and each of the bidentate donates\({\bf{2}}\)electrons and since we have\({\bf{2}}\)of them, they donate\({\bf{4}}\)electrons, and their sum is\({\bf{6}}\).
03

Result

\(\begin{aligned}{}a)Pt &= 4\\b){\rm{Pt}} &= 4\\c)Zn &= 4\\d)Zn &= 4\\e){\rm{Ni}} &= 6\\f){\rm{Fe}} &= 6\end{aligned}\)

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Most popular questions from this chapter

Give the coordination numbers and write the formulas for each of the following, including all isomers where appropriate:

(a) tetrahydroxozincate(II) ion (tetrahedral)

(b) hexacyanopalladate(IV) ion

(c) dichloroaurate(I) ion (note that aurum is Latin for “gold”)

(d) diamminedichloroplatinum(II)

(e) potassium diamminetetrachlorochromate(III)

(f) hexaamminecobalt(III) hexacyanochromate(III)

(g) dibromobis(ethylenediamine) cobalt(III) nitrate

Explain how the diphosphate ion, \({\left( {{O_3}P - O - P{O_3}} \right)^{4 - }}\) can function as a water softener that prevents the precipitation of \(F{e^{2 + }}\) as an insoluble iron salt.

A 2.5624-g sample of a pure solid alkali metal chloride is dissolved in water and treated with excess silver nitrate. The resulting precipitate, filtered and dried, weighs 3.03707 g. What was the percent by mass of chloride ion in the original compound? What is the identity of the salt?

Give the coordination number for each metal ion in the following compounds:

\(\begin{aligned}{}(a){\left( {Co{{\left( {C{O_3}} \right)}_3}} \right)^{3 - }}\\(b){\left( {Cu{{\left( {N{H_3}} \right)}_4}} \right)^{2 + }}\\(c){\left( {Co{{\left( {N{H_3}} \right)}_4}B{r_2}} \right)_2}{\left( {S{O_4}} \right)_3}\\(d)\left( {Pt{{\left( {N{H_3}} \right)}_4}} \right)\left( {PtC{l_4}} \right)\\(e)\left( {Cr{{(en)}_3}} \right){\left( {N{O_3}} \right)_3}\\(f)\left( {Pd{{\left( {N{H_3}} \right)}_2}B{r_2}} \right)\\(g){K_3}\left( {Cu{{(Cl)}_5}} \right)\\(h)\left( {Zn{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\end{aligned}\)

Draw the crystal field diagrams for \({\left( {Fe{{\left( {N{O_2}} \right)}_6}} \right)^{4 - }}\)and \({\left( {Fe{F_6}} \right)^{3 - }}.\)State whether each complex is high spin or low spin, paramagnetic or diamagnetic, and compare \({\Delta _{oct }}\)to \(P\)for each complex.

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