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Chapter 1: Problem 15

Liquid helium is extensively used in research on superconductivity. Liquid helium has a boiling point of \(4.22 \mathrm{~K}\). Express this boiling point in \({ }^{\circ} \mathrm{C}\) and \(^{\circ} \mathrm{F}\).

Short Answer

Expert verified
Answer: The boiling point of liquid helium in Celsius is -268.93°C, and in Fahrenheit, it is -452.07°F.

Step by step solution

01

Convert Kelvin to Celsius

To convert the given temperature from Kelvin to Celsius, we can use the following formula: \(T(^\circ C) = T(K) - 273.15\) Where: - \(T(^\circ C)\) is the temperature in Celsius - \(T(K)\) is the temperature in Kelvin In our case, \(T(K) = 4.22 \mathrm{~K}\). Plug this value into the formula and calculate the temperature in Celsius: \(T(^\circ C) = 4.22 - 273.15\)
02

Calculate the boiling point in Celsius

Now let's calculate the boiling point in Celsius: \(T(^\circ C) = 4.22 - 273.15 = -268.93^\circ C\) So the boiling point of liquid helium in Celsius is \(-268.93^\circ C\).
03

Convert Celsius to Fahrenheit

To convert the boiling point of liquid helium from Celsius to Fahrenheit, we'll use the following formula: \(T(^\circ F) = T(^\circ C) \times \frac{9}{5} + 32\) Where: - \(T(^\circ F)\) is the temperature in Fahrenheit - \(T(^\circ C)\) is the temperature in Celsius In our case, \(T(^\circ C) = -268.93^\circ C\). Plug this value into the formula and calculate the temperature in Fahrenheit: \(T(^\circ F) = -268.93 \times \frac{9}{5} + 32\)
04

Calculate the boiling point in Fahrenheit

Now let's calculate the boiling point in Fahrenheit: \(T(^\circ F) = -268.93 \times \frac{9}{5} + 32 = -452.07^\circ F\) So the boiling point of liquid helium in Fahrenheit is \(-452.07^\circ F\). In conclusion, the boiling point of liquid helium in Celsius is \(-268.93^\circ C\) and in Fahrenheit is \(-452.07^\circ F\).

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