Describe how you would prepare \(465 \mathrm{~mL}\) of \(0.3550 \mathrm{M}\) potassium dichromate solution starting with (a) solid potassium dichromate. (b) \(0.750 M\) potassium dichromate solution.

= 0.165025 moles Now that we have the number of moles of potassium dichromate needed, we can determine the mass of the solid potassium dichromate required. #tag_title# (a) Calculate the mass of solid potassium dichromate)#tag_content# To calculate the mass of solid potassium dichromate, we'll use the formula: mass = moles * molar mass The molar mass of potassium dichromate (K2Cr2O7) is approximately 294.18 g/mol. Therefore, the mass of solid potassium dichromate needed is: mass = 0.165025 moles * 294.18 g/mol = 48.531 g #tag_title# (b) Calculate the volume of the 0.750 M potassium dichromate solution)#tag_content# To determine the volume of the 0.750 M potassium dichromate solution needed, we'll use the dilution formula: M1 * V1 = M2 * V2 Where M1 and V1 are the molarity and volume of the initial solution (0.750 M), and M2 and V2 are the molarity and volume of the final solution (0.3550 M and 0.465 L). We want to find V1. V1 = (M2 * V2) / M1 V1 = (0.3550 * 0.465) / 0.750 = 0.219382 L Therefore, we need 0.219382 L or 219.382 mL of the 0.750 M potassium dichromate solution. #Answer Format# (a) To prepare 465 mL of 0.3550 M potassium dichromate solution using solid potassium dichromate, 48.531 g of solid potassium dichromate is needed. (b) To prepare 465 mL of 0.3550 M potassium dichromate solution using a 0.750 M potassium dichromate solution, 219.382 mL of the 0.750 M solution is required.