Chapter 10: Problem 30
The Henry's law constant for the solubility of oxygen in water is \(3.30 \times 10^{-4} \mathrm{M} / \mathrm{atm}\) at \(12^{\circ} \mathrm{C}\) and \(2.85 \times 10^{-4} \mathrm{M} / \mathrm{atm}\) at \(22^{\circ} \mathrm{C}\). Air is \(21 \mathrm{~mol} \%\) oxygen. (a) How many grams of axygen can be dissolved in one liter of a trout stream at \(12^{\circ} \mathrm{C}\left(54^{\circ} \mathrm{F}\right)\) at an air pressure of \(1.00 \mathrm{~atm} ?\) (b) How many grams of oxygen can be dissolved per liter in the same trout stream at \(22^{\circ} \mathrm{C}\left(72^{\circ} \mathrm{F}\right)\) at the same pressure as in (a)? (c) A nuclear power plant is responsible for the stream's increase in temperature. What percentage of dissolved oxygen is lost by this increase in the stream's temperature?
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