nsulin is a hormone responsible for the regulation of glucose levels in the blood. An aqueous solution of insulin has an osmotic pressure of \(2.5 \mathrm{~mm} \mathrm{Hg}\) at \(25^{\circ} \mathrm{C}\). It is prepared by dissolving \(0.100 \mathrm{~g}\) of insulin in enough water to make \(125 \mathrm{~mL}\) of solution. What is the molar mass of insulin?

Short Answer

Expert verified
Question: Calculate the molar mass of insulin from the given data: a 0.100 g sample of insulin yields an osmotic pressure of 2.5 mmHg when dissolved in 125 mL of water at 25°C. Answer: The molar mass of insulin is approximately 612.29 g/mol.

Step by step solution

01

Convert temperature to Kelvin

To use the osmotic pressure formula, convert the given temperature from Celsius to Kelvin: \(T = 25 + 273.15 = 298.15 \mathrm{K}\)
02

Convert the osmotic pressure to atm

We need to have the pressure in atmospheres, so convert the given osmotic pressure in mmHg to atm: \(2.5 \mathrm{~mmHg} \times \frac{1 \mathrm{~atm}}{760 \mathrm{~mmHg}} = 0.003289 \mathrm{~atm}\)
03

Calculate moles using the osmotic pressure formula

The osmotic pressure formula is given by: \(\Pi = n\frac{RT}{V}\) Rearranging for n we have, \(n = \frac{\Pi V}{RT}\) Now, plug in the values for pi (\(\Pi\)), the gas constant R (\(0.0821 \frac{\mathrm{L\cdot atm}}{\mathrm{mol\cdot K}}\)), T, and volume in L (V): \(n = \frac{0.003289 \cdot 0.125}{0.0821 \cdot 298.15} = 1.63247 \times 10^{-4}\ \mathrm{mol}\)
04

Calculating molar mass

Using the moles (n) and mass (0.100 g) of insulin, find the molar mass. Molar mass = \(\frac{mass}{moles}\) Molar mass = \(\frac{0.100}{1.63247 \times 10^{-4}} = 612.29 \mathrm{g/mol}\) Thus, the molar mass of insulin is approximately \(612.29 \mathrm{g/mol}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Osmotic Pressure
Osmotic pressure is a fundamental concept in chemistry that deals with the pressure required to stop the flow of a solvent into a solution through a semipermeable membrane. This flow is due to the natural tendency of a system to balance concentrations on either side of the membrane, a process known as osmosis. When a solution is separated from a pure solvent by a membrane that only allows the solvent to pass through, the solvent naturally moves into the solution. The osmotic pressure \( \Pi \) can be quantified using a formula derived from the ideal gas law: \( \Pi = nRT/V \), where \( n \) is the number of moles of solute, \( R \) is the gas constant, \( T \) is temperature in Kelvin, and \( V \) is the volume of the solution in liters.

Understanding osmotic pressure is crucial for biological and chemical sciences, as it's involved in many physiological processes, such as the regulation of blood glucose levels by insulin. In laboratory settings, measuring the osmotic pressure of a solution can help determine the molar mass of an unknown solute, as illustrated in the exercise where we calculated the molar mass of insulin.
Colligative Properties
Colligative properties are the physical properties of solutions that depend on the number of particles (molecules or ions) present in the solution, rather than the identity of the solute particles. These properties include boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure.

For example, when a solute is dissolved in a solvent, the boiling point of the solution increases because the presence of solute particles interferes with the natural escape of solvent particles into the gas phase. Similarly, the freezing point of a solution is lower than that of the pure solvent because the solute disrupts the crystalline structure formation of the freezing solvent.

Osmotic pressure is also a colligative property and it’s used in the exercise to find the molar mass of insulin. This is because osmotic pressure is directly proportional to the number of solute particles, making it an invaluable tool for determining molecular quantities without needing to know the chemical identity of the solute.
Gas Laws in Chemistry
The gas laws in chemistry describe the behavior of gases in relation to pressure, volume, and temperature. These laws are critical for understanding and predicting how gases will behave under different conditions. The ideal gas law, \( PV = nRT \), combines several simpler gas laws and relates the pressure (P), volume (V), moles of gas (n), temperature in Kelvin (T), and the universal gas constant (R).

In practice, the ideal gas law can be applied to situations where gases behave ideally, meaning there are no interactions between the gas particles and the volume of individual particles is negligible compared to the space the gas occupies. Although real gases do not always follow the ideal model perfectly, it provides a close approximation that is useful in many scenarios, including the calculation of osmotic pressure as shown in the molar mass determination of insulin.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Silver ions can be found in some of the city water piped into homes. The average concentration of silver ions in city water is \(0.028\) ppm. (a) How many milligrams of silver ions would you ingest daily if you drank eight glasses (eight oz/glass) of city water daily? (b) How many liters of city water are required to recover \(1.00 \mathrm{~g}\) of silver chemically?

Pure benzene boils at \(80.10^{\circ} \mathrm{C}\) and has a boiling point constant, \(k_{\mathrm{b}}\), of \(2.53^{\circ} \mathrm{C} / \mathrm{m} .\) A sample of benzene is contaminated by naphthalene, \(\mathrm{C}_{10} \mathrm{H}_{8}\). The boiling point of the contaminated sample is \(81.20^{\circ} \mathrm{C}\). How pure is the sample? (Express your answer as mass percent of benzene.)

The water-soluble nonelectrolyte \(\mathrm{X}\) has a molar mass of \(410 \mathrm{~g} / \mathrm{mol}\). A \(0.100\) -g mixture containing this substance and sugar \((\mathrm{MM}=342 \mathrm{~g} / \mathrm{mol})\) is added to \(1.00 \mathrm{~g}\) of water to give a solution whose freezing point is \(-0.500^{\circ} \mathrm{C}\). Estimate the mass percent of \(\mathrm{X}\) in the mixture.

What is the osmotic pressure of a \(0.250 \mathrm{M}\) solution of \(\mathrm{K}_{2} \mathrm{CO}_{3}\) at \(25^{\circ} \mathrm{C}\) ? (Assume complete dissociation.)

Lead is a poisonous metal that especially affects children because they retain a larger fraction of lead than adults do. Lead levels of \(0.250 \mathrm{ppm}\) in a child cause delayed cognitive development. How many moles of lead present in \(1.00 \mathrm{~g}\) of a child's blood would \(0.250 \mathrm{ppm}\) represent?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free