Silver ions can be found in some of the city water piped into homes. The average concentration of silver ions in city water is \(0.028\) ppm. (a) How many milligrams of silver ions would you ingest daily if you drank eight glasses (eight oz/glass) of city water daily? (b) How many liters of city water are required to recover \(1.00 \mathrm{~g}\) of silver chemically?

Short Answer

Expert verified
Answer: By drinking eight glasses of city water daily, you would ingest approximately 0.0530 milligrams of silver ions. Approximately 35,714.29 liters of city water are required to recover 1.00 gram of silver chemically.

Step by step solution

01

Convert concentration from ppm to mg/L

To convert the concentration of silver ions in city water from ppm to mg/L, simply keep the value the same. So, the concentration of silver ions in city water is 0.028 mg/L.
02

Calculate the volume of water consumed in liters

Each glass of water contains 8 oz. So, eight glasses contain 8 x 8 = 64 oz of water. To convert ounces to liters, we will use the conversion factor 1 L = 33.814 oz. Volume (in liters) = (64 oz) x (1 L / 33.814 oz) ≈ 1.8927 L
03

Calculate the amount of silver ions ingested daily

To calculate the amount of silver ions ingested daily, we will use the following formula: Amount of silver ions (in mg) = Concentration (in mg/L) x Volume of water (in L) Amount of silver ions (in mg) = (0.028 mg/L) x (1.8927 L) ≈ 0.0530 mg So, by drinking eight glasses of city water daily, you would ingest approximately 0.0530 milligrams of silver ions.
04

Calculate the amount of city water required to recover 1 gram of silver

Given that 0.028 mg of silver ions are present in 1 L of city water, we need to find how many liters of city water are required to have 1 gram (1000 mg) of silver ions. We will use the following formula: Volume of water (in L) = Amount of silver ions (in mg) / Concentration (in mg/L) Volume of water (in L) = (1000 mg) / (0.028 mg/L) ≈ 35714.29 L So, approximately 35,714.29 liters of city water are required to recover 1.00 gram of silver chemically.

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