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Chapter 10: Problem 6

Lead is a poisonous metal that especially affects children because they retain a larger fraction of lead than adults do. Lead levels of \(0.250 \mathrm{ppm}\) in a child cause delayed cognitive development. How many moles of lead present in \(1.00 \mathrm{~g}\) of a child's blood would \(0.250 \mathrm{ppm}\) represent?

Short Answer

Expert verified
Moles of lead = (1.00 g x (0.250/1000000))/207.2 g/mol = 1.2077 × 10^-6 mol Thus, there are 1.2077 × 10^-6 moles of lead present in 1.00 g of a child's blood with a concentration of 0.250 ppm.

Step by step solution

01

Convert ppm to mass fraction

Parts per million (ppm) is a unit of concentration that indicates 1 part in 1000000 parts. We will convert the given lead concentration (0.250 ppm) to mass fraction for further calculations. 1 ppm = 1 part in 1000000 parts = 1/1000000 So, 0.250 ppm = 0.250/1000000
02

Find the mass of lead in 1.00 g of blood

Now that we have the mass fraction of lead in the blood, we will find the mass of lead in 1.00 g of blood. Mass of lead = Mass of blood x Mass fraction of lead Mass of lead = 1.00 g x (0.250/1000000)
03

Convert mass to moles using the molar mass of lead

To find the moles of lead, we will divide the mass of lead by the molar mass of lead. The molar mass of lead (Pb) is 207.2 g/mol. Moles of lead = Mass of lead / Molar mass of lead Moles of lead = (1.00 g x (0.250/1000000))/207.2 g/mol Now, calculate the moles of lead.

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