Chapter 11: Problem 54
Ammonium cyanate, \(\mathrm{NH}_{4} \mathrm{NCO}\), in water rearranges to produce urea, a common fertilizer, \(\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO}\) : $$\mathrm{NH}_{4} \mathrm{NCO}(a q) \longrightarrow\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO}(a q)$$ The rearrangement is a second-order reaction. It takes \(11.6 \mathrm{~h}\) for the concentration of \(\mathrm{NH}_{4} \mathrm{NCO}\) to go from \(0.250 \mathrm{M}\) to \(0.0841 \mathrm{M}\). (a) What is \(k\) for the reaction? (b) What is the half-life of the reaction when \(\mathrm{NH}_{4} \mathrm{NCO}\) is \(0.100 \mathrm{M}\) ? (c) How long will it take to rearrange \(39 \%\) of a \(0.450 \mathrm{M}\) solution? (d) How fast is a \(0.839 \mathrm{M}\) solution being changed to urea?
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