The activation energy for the reaction involved in the souring of raw milk is \(75 \mathrm{~kJ}\). Milk will sour in about eight hours at \(21^{\circ} \mathrm{C}\left(70^{\circ} \mathrm{F}=\right.\) room temperature). How long will raw milk last in a refrigerator maintained at \(5^{\circ} \mathrm{C}\) ? Assume the rate constant to be inversely related to souring time.

Short Answer

Expert verified
Answer: Approximately 81.56 hours, or about 3.4 days.

Step by step solution

01

Convert temperatures to Kelvin

To work with absolute temperatures, we need to convert the given temperatures in Celsius to Kelvin. To do so, simply add 273.15 to the Celsius temperatures. $$ T_1 = 21^{\circ}\mathrm{C} + 273.15 = 294.15\mathrm{K} $$ $$ T_2 = 5^{\circ}\mathrm{C} + 273.15 = 278.15\mathrm{K} $$
02

Use the Arrhenius equation to find the relationship between rate constants and temperature

We will use the following form of the Arrhenius equation: $$ \frac{k_2}{k_1} = \exp \left(\frac{-E_\mathrm{a}}{R} \left(\frac{1}{T_2} - \frac{1}{T_1}\right) \right) $$ Where \(k_1\) is the rate constant at temperature \(T_1\), \(k_2\) is the rate constant at temperature \(T_2\), \(E_\mathrm{a}\) is the activation energy, and \(R\) is the ideal gas constant (8.314 J/mol K). We are given that \(E_\mathrm{a} = 75\mathrm{kJ/mol}\) which is equal to 75,000 J/mol, and since the rate constant \(k\) is inversely related to souring time: $$ \frac{t_1}{t_2} = \exp \left(\frac{-75,000}{8.314} \left(\frac{1}{278.15} - \frac{1}{294.15}\right) \right) $$
03

Calculate the souring time at the refrigerator temperature

We are given that \(t_1\), the souring time at \(21^{\circ}\mathrm{C}\), is 8 hours. We'll substitute this value and solve for \(t_2\), the souring time at \(5^{\circ}\mathrm{C}\): $$ \frac{8}{t_2} = \exp \left(\frac{-75,000}{8.314} \left(\frac{1}{278.15} - \frac{1}{294.15}\right) \right) $$ Solve for \(t_2\): $$ t_2 = \frac{8}{\exp \left(\frac{-75,000}{8.314} \left(\frac{1}{278.15} - \frac{1}{294.15}\right) \right)} $$ When we plug the numbers into the equation, we get: $$ t_2 \approx 81.56 \mathrm{~hours} $$ So, raw milk will last about 81.56 hours, or approximately 3.4 days, in a refrigerator maintained at \(5^{\circ}\mathrm{C}\).

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