Write the rate expression for each of the following elementary steps: (a) \(\mathrm{NO}_{3}+\mathrm{CO} \longrightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2}\) (b) \(\mathrm{I}_{2} \longrightarrow 2 \mathrm{I}\) (c) \(\mathrm{NO}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}_{3}\)

Short Answer

Expert verified
For the given elementary steps, the rate expressions are: (a) Rate = k[NO3][CO] (b) Rate = k[I2] (c) Rate = k[NO][O2]

Step by step solution

01

(a) Write the rate expression for \(\mathrm{NO}_3+\mathrm{CO}\longrightarrow\mathrm{NO}_2+\mathrm{CO}_2\)

For this elementary step, the reaction equation is: \(\mathrm{NO}_3+\mathrm{CO}\longrightarrow\mathrm{NO}_2+\mathrm{CO}_2\) since the stoichiometric coefficients are 1 for each reactant, the rate expression will be: Rate = k[NO3]^[1] x [CO]^[1] = k[NO3][CO]
02

(b) Write the rate expression for \(\mathrm{I}_2\longrightarrow 2\mathrm{I}\)

For this elementary step, the reaction equation is: \(\mathrm{I}_2\longrightarrow 2\mathrm{I}\) since the stoichiometric coefficient is 1 for \(\mathrm{I}_2\), the rate expression will be: Rate = k[I2]^[1] = k[I2]
03

(c) Write the rate expression for \(\mathrm{NO}+\mathrm{O}_2\longrightarrow \mathrm{NO}_3\)

For this elementary step, the reaction equation is: \(\mathrm{NO}+\mathrm{O}_2\longrightarrow \mathrm{NO}_3\) since the stoichiometric coefficients are 1 for each reactant, the rate expression will be: Rate = k[NO]^[1] x [O2]^[1] = k[NO][O2]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Step
An elementary step in chemical reactions is a single reaction stage that describes a change that happens in a single, decisive step. It represents a fundamental building block of complex reactions that occur through multiple steps. Each elementary step is characterized by its molecularity, which refers to the number of reactant molecules involved.

For instance, when we look at the elementary step \(\mathrm{NO}_3+\mathrm{CO}\longrightarrow\mathrm{NO}_2+\mathrm{CO}_2\), we're observing a bimolecular reaction involving two species, \(\mathrm{NO}_3\) and \(\mathrm{CO}\), undergoing a direct transformation without any intermediate stages. In contrast, a unimolecular reaction like \(\mathrm{I}_2\longrightarrow\mathrm{I}\) only involves a single molecule breaking apart.

To ensure students fully comprehend this concept, remember that an elementary step assumes a direct conversion from reactants to products, as described in the problem's solutions.
Chemical Kinetics
Chemical kinetics is the branch of chemistry that deals with the rates of chemical reactions and the factors that affect these rates. It involves the study of how different variables such as concentration, temperature, and catalysts impact the speed at which reactants are converted into products.

Understanding the kinetics of a reaction provides insight into the reaction mechanism, which is the step-by-step sequence of elementary steps that describes the pathway from reactants to products. For example, the rate at which \(\mathrm{NO}_3\) and \(\mathrm{CO}\) react to form \(\mathrm{NO}_2\) and \(\mathrm{CO}_2\) is determined by factors such as the frequency of collisions and the energy of the reactant molecules. Kinetics is not only about speed but also about the detailed process of how reactions proceed, which can often involve complex sequences of elementary steps.

To improve understanding, emphasize that kinetics is more than just measuring reaction speed; it's about dissecting the dynamic process of the chemical reaction itself.
Reaction Rate Law
The reaction rate law, also simply known as the rate law, expresses the relationship between the rate of a chemical reaction and the concentration of its reactants. For an elementary step, the rate law is derived directly from the reaction stoichiometry, held true for most elementary reactions. The exponents in a rate law correspond to the stoichiometric coefficients of the reactants for an elementary step.

Consider the examples given in the exercise, each rate expression corresponds to the formula 'Rate = k[Reactant1]^[m] [Reactant2]^[n]...', where 'k' is the rate constant, and 'm' and 'n' are the reaction orders with respect to each reactant. For example, the rate law for the reaction of \(\mathrm{NO}\) with \(\mathrm{O}_2\) to form \(\mathrm{NO}_3\) is Rate = k[NO][O2], indicating that the rate is proportional to the concentration of both \(\mathrm{NO}\) and \(\mathrm{O}_2\).

To make this digestible for students, emphasize that the rate law is a mathematical way to predict how changes in reactant concentrations will influence the reaction rate, adhering to the specific molecularity of the elementary steps involved.

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Most popular questions from this chapter

The decomposition of phosphine, \(\mathrm{PH}_{3}\), to \(\mathrm{P}_{4}(g)\) and \(\mathrm{H}_{2}(g)\) is firstorder. Its rate constant at a certain temperature is \(1.1 \mathrm{~min}^{-1}\). (a) What is its half-life in seconds? (b) What percentage of phosphine is decomposed after \(1.25 \mathrm{~min}\) ? (c) How long will it take to decompose one fifth of the phosphine?

Ammonia is produced by the reaction between nitrogen and hydro- gen gases. (a) Write a balanced equation using smallest whole-number coefficients for the reaction. (b) Write an expression for the rate of reaction in terms of \(\Delta\left[\mathrm{NH}_{3}\right]\). (c) The concentration of ammonia increases from \(0.257 \mathrm{M}\) to \(0.815 \mathrm{M}\) in \(15.0 \mathrm{~min} .\) Calculate the average rate of reaction over this time interval.

The decomposition of sulfuryl chloride, \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\), to sulfur dioxide and chlorine gases is a first-order reaction. $$\mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{Cl}_{2}(g)$$ At a certain temperature, the half-life of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) is \(7.5 \times 10^{2} \mathrm{~min}\). Consider a sealed flask with \(122.0 \mathrm{~g}\) of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) (a) How long will it take to reduce the amount of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) in the sealed flask to \(45.0 \mathrm{~g}\) ? (b) If the decomposition is stopped after \(29.0 \mathrm{~h}\), what volume of \(\mathrm{Cl}_{2}\) at \(27^{\circ} \mathrm{C}\) and \(1.00\) atm is produced?

For the reaction $$5 \mathrm{Br}^{-}(a q)+\mathrm{BrO}_{3}^{-}(a q)+6 \mathrm{H}^{+}(a q) \longrightarrow 3 \mathrm{Br}_{2}(a q)+3 \mathrm{H}_{2} \mathrm{O}$$ it was found that at a particular instant bromine was being formed at the rate of \(0.039 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\). At that instant, at what rate is (a) water being formed? (b) bromide ion being oxidized? (c) \(\mathrm{H}^{+}\) being consumed?

Experimental data are listed for the hypothetical reaction $$\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}+\mathrm{D}$$ $$\begin{array}{lcccccc}\hline \text { Time (s) } & 0 & 10 & 20 & 30 & 40 & 50 \\\\{[\mathrm{~A}]} & 0.32 & 0.24 & 0.20 & 0.16 & 0.14 & 0.12 \\ \hline\end{array}$$ (a) Plot these data as in Figure \(11.2\). (b) Draw a tangent to the curve to find the instantaneous rate at \(30 \mathrm{~s}\). (c) Find the average rate over the 10 to \(40 \mathrm{~s}\) interval. (d) Compare the instantaneous rate at \(30 \mathrm{~s}\) with the average rate over the thirty-second interval.

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