Write the rate expression for each of the following elementary steps: (a) \(\mathrm{NO}+\mathrm{O}_{3} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}_{2}\) (b) \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2}\) (c) \(\mathrm{K}+\mathrm{HCl} \longrightarrow \mathrm{KCl}+\mathrm{H}\)

Short Answer

Expert verified
Question: Write the rate expression for each of the following elementary reactions: (a) NO + O3 → NO2 + O2 (b) 2NO2 → 2NO + O2 (c) K + HCl → KCl + H Answer: (a) Rate = k [NO][O3] (b) Rate = k [NO2]^2 (c) Rate = k [K][HCl]

Step by step solution

01

Reaction (a) - Identify Reactants and Molecularity

In the first reaction, we have \(\mathrm{NO}\) and \(\mathrm{O}_{3}\) as reactants. Each reactant has a molecularity of 1 because there is only one molecule involved in the reaction.
02

Reaction (a) - Write Rate Expression

For reaction (a), the rate expression is given by: $$ \text{Rate} = k [\mathrm{NO}]^1 [\mathrm{O}_{3}]^1 $$
03

Reaction (b) - Identify Reactants and Molecularity

In the second reaction, we have \(\mathrm{NO}_{2}\) as the reactant. It has a molecularity of 2 because there are two molecules involved in the reaction.
04

Reaction (b) - Write Rate Expression

For reaction (b), the rate expression is given by: $$ \text{Rate} = k [\mathrm{NO}_{2}]^2 $$
05

Reaction (c) - Identify Reactants and Molecularity

In the third reaction, we have \(\mathrm{K}\) and \(\mathrm{HCl}\) as reactants. Each reactant has a molecularity of 1 because there is only one molecule involved in the reaction.
06

Reaction (c) - Write Rate Expression

For reaction (c), the rate expression is given by: $$ \text{Rate} = k [\mathrm{K}]^1 [\mathrm{HCl}]^1 $$ To summarize, the rate expressions for the given elementary reactions are: (a) \(\text{Rate} = k [\mathrm{NO}] [\mathrm{O}_{3}]\) (b) \(\text{Rate} = k [\mathrm{NO}_{2}]^2\) (c) \(\text{Rate} = k [\mathrm{K}] [\mathrm{HCl}]\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is an essential aspect of chemistry that studies the speed or rate at which a chemical reaction occurs and determines the factors influencing it. This field helps us understand how various conditions like temperature, concentration, and presence of catalysts can affect the rate of a reaction.

Understanding chemical kinetics allows us to predict how long it will take for a reaction to complete and what yield of products we can expect over time. It also plays a pivotal role in industries, where the efficiency of chemical processes can mean the difference between a profitable operation and a costly one.

When we talk about rate expressions, such as, \( \text{Rate} = k [\mathrm{NO}] [\mathrm{O}_{3}] \), the \(k\) in the equation represents the rate constant, which is specific to each reaction and can be influenced by external conditions. The rate constant is central to kinetical analyses, as it is a quantification of how fast the reaction proceeds under certain conditions.
Elementary Reaction Steps
Elementary reaction steps are the simplest reactions in which reactants convert to products in a single step and with a single transition state. These steps are crucial building blocks to understanding complex reactions, which happen in multiple stages.

An important feature of elementary reactions is how their rate expressions reflect the stoichiometry of the reactants involved. For example, the elementary reaction for the formation of \(\mathrm{NO}_{2}\) and \(\mathrm{O}_{2}\) from \(\mathrm{NO}\) and \(\mathrm{O}_{3}\) has a rate expression directly related to the concentrations of the reactants.

In a multi-step reaction, however, the overall rate expression can be more complex and is not always apparent from the stoichiometry of the overall reaction. Kinetic studies, often involving experiments, are utilized to determine the individual steps and their respective rate expressions.
Reaction Molecularity
Reaction molecularity refers to the number of reactant particles involved in an elementary reaction step. It is a key concept in understanding how reactants interact to form products.

Unimolecular and Bimolecular Reactions

Reactions can be classified as unimolecular or bimolecular. A unimolecular reaction involves a single molecule undergoing a transformation, while a bimolecular reaction involves two reactant molecules colliding and reacting together.

Using the reactions provided as examples, the conversion of \(\mathrm{NO}_{2}\) to \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) in reaction (b) is a bimolecular step, as it involves two \(\mathrm{NO}_{2}\) molecules. The rate expression (\text{Rate} = k [\mathrm{NO}_{2}]^2) highlights this by squaring the concentration of \(\mathrm{NO}_{2}\).

Molecularity can also provide insights into the underlying reaction mechanism and is a fundamental concept that links the microscopic interactions of molecules to the macroscopic observable rate of a reaction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The decomposition of \(\mathrm{A}\) at \(85^{\circ} \mathrm{C}\) is a zero-order reaction. It takes 35 minutes to decompose \(37 \%\) of an initial mass of \(282 \mathrm{mg}\). (a) What is \(k\) at \(85^{\circ} \mathrm{C}\) ? (b) What is the half-life of \(282 \mathrm{mg}\) at \(85^{\circ} \mathrm{C}\) ? (c) What is the rate of decomposition for \(282 \mathrm{mg}\) at \(85^{\circ} \mathrm{C} ?\) (d) If one starts with \(464 \mathrm{mg}\), what is the rate of its decomposition at \(85^{\circ} \mathrm{C} ?\)

Derive the integrated rate law, \([\mathrm{A}]=[\mathrm{A}]_{0}-k t\), for a zero-order reaction. (Hint: Start with the relation \(-\Delta[\mathrm{A}]=k \Delta \mathrm{t}\).)

Ammonium cyanate, \(\mathrm{NH}_{4} \mathrm{NCO}\), in water rearranges to produce urea, a common fertilizer, \(\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO}\) : $$\mathrm{NH}_{4} \mathrm{NCO}(a q) \longrightarrow\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO}(a q)$$ The rearrangement is a second-order reaction. It takes \(11.6 \mathrm{~h}\) for the concentration of \(\mathrm{NH}_{4} \mathrm{NCO}\) to go from \(0.250 \mathrm{M}\) to \(0.0841 \mathrm{M}\). (a) What is \(k\) for the reaction? (b) What is the half-life of the reaction when \(\mathrm{NH}_{4} \mathrm{NCO}\) is \(0.100 \mathrm{M}\) ? (c) How long will it take to rearrange \(39 \%\) of a \(0.450 \mathrm{M}\) solution? (d) How fast is a \(0.839 \mathrm{M}\) solution being changed to urea?

For the reaction $$5 \mathrm{Br}^{-}(a q)+\mathrm{BrO}_{3}^{-}(a q)+6 \mathrm{H}^{+}(a q) \longrightarrow 3 \mathrm{Br}_{2}(a q)+3 \mathrm{H}_{2} \mathrm{O}$$ it was found that at a particular instant bromine was being formed at the rate of \(0.039 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\). At that instant, at what rate is (a) water being formed? (b) bromide ion being oxidized? (c) \(\mathrm{H}^{+}\) being consumed?

In a first-order reaction, suppose that a quantity \(X\) of a reactant is added at regular intervals of time, \(\Delta t\). At first the amount of reactant in the system builds up; eventually, however, it levels off at a saturation value given by the expression $$\text { saturation value }=\frac{X}{1-10^{-a}} \quad \text { where } a=0.30 \frac{\Delta t}{t_{1 / 2}}$$ This analysis applies to prescription drugs, of which you take a certain amount each day. Suppose that you take \(0.100 \mathrm{~g}\) of a drug three times a day and that the half-life for elimination is \(2.0\) days. Using this equation, calculate the mass of the drug in the body at saturation. Suppose further that side effects show up when \(0.500 \mathrm{~g}\) of the drug accumulates in the body. As a pharmacist, what is the maximum dosage you could assign to a patient for an 8 -h period without causing side effects?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free