Learning Materials
Features
Discover
Chapter 13: Problem 20
Solution \(\mathrm{X}\) has \(\mathrm{pH}\) 11.7. Solution \(\mathrm{Y}\) has \(\left[\mathrm{OH}^{-}\right]=4.5 \times 10^{-2}\). Which solution is more basic? Which has the higher \(\mathrm{pOH}\) ?
Over 30 million students worldwide already upgrade their learning with Vaia!
All the tools & learning materials you need for study success - in one app.
Get started for free
Para-aminobenzoic acid (PABA), \(\mathrm{HC}_{7} \mathrm{H}_{6} \mathrm{NO}_{2}\), is used in some sunscreen agents. A solution is made by dissolving \(0.263\) mol of PABA in enough water to make \(750.0 \mathrm{~mL}\) of solution. The solution has \(\left[\mathrm{H}^{+}\right]=2.6 \times 10^{-3} \mathrm{M}\). What is \(K_{\mathrm{a}}\) for PABA?
Using the Brønsted-Lowry model, write an equation to show why each of the following species produces a basic aqueous solution. (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{NO}_{2}^{-}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (d) \(\mathrm{CO}_{3}{ }^{2-}\) (e) \(\mathrm{F}^{-}\) (f) \(\mathrm{HCO}_{3}^{-}\)
What is the \(\mathrm{pH}\) of a solution obtained by adding \(5.00 \mathrm{~g}\) of \(\mathrm{HI}\) to \(295 \mathrm{~mL}\) of a \(0.786 M\) solution of \(\mathrm{HNO}_{3} ?\) Assume that the HI addition does not change the volume of the resulting solution.
Arrange the following \(0.1 M\) aqueous solutions in order of decreasing \(\mathrm{pH}\) (highest to lowest). \(\begin{array}{lllll}\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}, & \mathrm{HNO}_{3}, & \mathrm{NH}_{4} \mathrm{NO}_{3}, & \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}, & \mathrm{NaF}\end{array}\)
For each of the following reactions, indicate the Brønsted-Lowry acids and bases. What are the conjugate acid/base pairs? (a) \(\mathrm{H}_{3} \mathrm{O}^{+}(a q)+\mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{HCN}(a q)+\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{HNO}_{2}(a q)+\mathrm{OH}^{-}(a q) \rightleftharpoons \mathrm{NO}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{HCHO}_{2}(a q)+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CHO}_{2}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q)\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.
Explanations 
Textbooks 
Exams 
GCSE 
IGCSE 
AS 
A Level 
International A Level 
University Admissions Tests 
Flashcards 
Vaia AI 
Notes 
Study Plans 
Study Sets 
Find a job 
Find a degree 
Student Deals 
Magazine 
Mobile App