Calculate \(K_{a}\) for the weak acids that have the following \(\mathrm{pK}_{\mathrm{a}}\) values. (a) \(3.9\) (b) \(10.12\) (c) \(13.07\)

Short Answer

Expert verified
Question: Calculate the Ka values for weak acids with the following pKa values: (a) 3.9, (b) 10.12, (c) 13.07. Answer: The Ka values for the weak acids with the given pKa values are: (a) 1.26 × 10^-4, (b) 7.58 × 10^-11, (c) 8.56 × 10^-14.

Step by step solution

01

Write down the given values and formula

(Write the \(\mathrm{pK}_a\) values for each part (a), (b), and (c) and the formula \(\mathrm{pK}_a = -\log_{10}(K_a)\). (a) \(\mathrm{pK}_a = 3.9\) (b) \(\mathrm{pK}_a = 10.12\) (c) \(\mathrm{pK}_a = 13.07\) Formula: \(\mathrm{pK}_a = -\log_{10}(K_a)\)
02

Calculate the \(K_a\) values

(Use the formula to find the \(K_a\) values for each part (a), (b), and (c).) (a) \(K_a = 10^{-\mathrm{pK}_a} = 10^{-3.9}\) The \(K_a\) for part (a) is: \(K_{a} \approx 1.26 \times 10^{-4}\) (b) \(K_a = 10^{-\mathrm{pK}_a} = 10^{-10.12}\) The \(K_a\) for part (b) is: \(K_{a} \approx 7.58 \times 10^{-11}\) (c) \(K_a = 10^{-\mathrm{pK}_a} = 10^{-13.07}\) The \(K_a\) for part (c) is: \(K_{a} \approx 8.56 \times 10^{-14}\) The \(K_a\) values for the weak acids with the given \(\mathrm{pK}_a\) values are: (a) \(1.26 \times 10^{-4}\) (b) \(7.58 \times 10^{-11}\) (c) \(8.56 \times 10^{-14}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free