Ascorbic acid, \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}\), also known as vitamin \(\mathrm{C}\), is present in many citrus fruits. It is a diprotic acid with the following \(K_{\mathrm{a}}\) values: \(K_{\mathrm{al}}=7.9 \times 10^{-5}\); \(K_{\mathrm{a} 2}=1.6 \times 10^{-12}\). What is the \(\mathrm{pH}\) of a \(0.63 \mathrm{M}\) solution of ascorbic acid? Estimate \(\left[\mathrm{HC}_{6} \mathrm{H}_{6} \mathrm{O}_{6}^{-}\right]\) and \(\left[\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}{ }^{2-}\right]\).

Short Answer

Expert verified
Question: Calculate the pH of a 0.63 M solution of ascorbic acid and estimate the concentrations of HC6H6O6- and C6H6O6²⁻, given Ka1 = 7.9 x 10⁻⁵ and Ka2 = 1.6 x 10⁻¹².

Step by step solution

01

Write the ionization steps and the corresponding Ka expressions for ascorbic acid#

The ionization process for ascorbic acid can be described in two steps: 1st ionization step: H2C6H6O6 (aq) <=> H+ (aq) + HC6H6O6⁻ (aq) Ka1 = [H+][HC6H6O6⁻]/[H2C6H6O6] 2nd ionization step: HC6H6O6⁻ (aq) <=> H+ (aq) + C6H6O6²⁻ (aq) Ka2 = [H+][C6H6O6²⁻]/[HC6H6O6⁻] Given that Ka1 = 7.9 x 10⁻⁵ and Ka2 = 1.6 x 10⁻¹².

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