Consider the following six beakers. All have \(100 \mathrm{~mL}\) of aqueous \(0.1 \mathrm{M}\) solutions of the following compounds: beaker A has HI beaker B has \(\mathrm{HNO}_{2}\) beaker \(\mathrm{C}\) has \(\mathrm{NaOH}\) beaker \(\mathrm{D}\) has \(\mathrm{Ba}(\mathrm{OH})_{2}\) beaker \(\mathrm{E}\) has \(\mathrm{NH}_{4} \mathrm{Cl}\) beaker \(\mathrm{F}\) has \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}\)

Short Answer

Expert verified
Based on the analysis of the six beakers containing 100 mL of 0.1 M aqueous solutions with different compounds, categorize each beaker as acid, base, or neutral and rank them in order of pH from lowest to highest. Beaker A: Strong acid - pH 1 Beaker B: Weak acid - Approximately between pH 1 and 7 Beaker C: Strong base - pH 13 Beaker D: Strong base - pH 12.3 Beaker E: Weak acid - Approximately between pH 1 and 7 Beaker F: Weak base - Approximately between pH 7 and 13

Step by step solution

01

Identify the compounds as acids or bases

First, let's identify each compound as either an acid, base, or neutral. - Beaker A (HI): HI is a strong acid, so it donates protons (H+) to the solution. - Beaker B (HNO2): HNO2 is a weak acid, so it partially donates protons (H+) to the solution. - Beaker C (NaOH): NaOH is a strong base, so it donates hydroxide ions (OH-) to the solution. - Beaker D (Ba(OH)2): Ba(OH)2 is also a strong base, and it donates two hydroxide ions per mole (2 OH-) to the solution. - Beaker E (NH4Cl): NH4Cl is the salt of a weak base (NH3) and a strong acid (HCl), so it primarily acts as a weak acid in solution and donates protons. - Beaker F (C2H5NH2): C2H5NH2 is a weak base (amine) that accepts protons in solution.
02

Calculate the pH of the solutions

For strong acids and bases, we can directly calculate the pH from their concentrations. For weak acids and bases, we will use approximations, as they do not fully dissociate. - Beaker A: HI is a strong acid, so the pH = -log([H+]) = -log(0.1) = 1 - Beaker B: HNO2 is a weak acid, so we can approximate the pH to be between 1 and 7 - Beaker C: NaOH is a strong base, so the pOH = -log([OH-]) = -log(0.1) = 1, then pH = 14 - pOH = 14 - 1 = 13 - Beaker D: Ba(OH)2 is a strong base, so the pOH = -log([2*0.1]) = -log(0.2), then pH = 14 - pOH ≈ 12.3 - Beaker E: NH4Cl acts as a weak acid, so we can approximate the pH to be between 1 and 7 - Beaker F: C2H5NH2 is a weak base, so we can approximate the pH to be between 7 and 13
03

Rank the solutions according to their pH

Now that we have an estimate for the pH of each solution, let's rank them from lowest to highest pH: 1. Beaker A: pH 1 2. Beaker B: Approximately between 1 and 7 3. Beaker E: Approximately between 1 and 7 4. Beaker F: Approximately between 7 and 13 5. Beaker D: pH 12.3 6. Beaker C: pH 13 This ranking gives us a general idea of the relative acidity and basicity of each solution, with A being the most acidic and C being the most basic.

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