For the system hemoglobin \(\cdot \mathrm{O}_{2}(a q)+\mathrm{CO}(g) \rightleftharpoons\) hemoglobin \(\cdot \mathrm{CO}(a q)+\mathrm{O}_{2}(g)\) \(K=2.0 \times 10^{2} .\) What must be the ratio of \(P_{\mathrm{Co}} / P_{\mathrm{O}_{2}}\) if \(12.0 \%\) of the hemoglobin in the bloodstream is converted to the CO complex?

Short Answer

Expert verified
Answer: The partial pressure ratio of CO to O2, \(P_{\mathrm{Co}} / P_{\mathrm{O}_{2}}\), is approximately \(7.6 \times 10^{-4}\).

Step by step solution

01

Write the equilibrium expression

Let \(H\) represent hemoglobin. The equilibrium reaction can be represented as: $$H \cdot O_{2} \oplus CO \rightleftharpoons H \cdot CO \oplus O_{2}$$ Now we can write the equilibrium expression as: $$K = \frac{[H \cdot CO][O_{2}]}{[H \cdot O_{2}][CO]}$$
02

Determine the concentrations

Since 12% of hemoglobin is converted to the CO complex, we know that the concentration of hemoglobin combined with CO is equal to 0.12 times the total hemoglobin concentration. So, \([H \cdot CO] = 0.12[H]_0\), where \([H]_0\) is the initial hemoglobin concentration. And since 88% of hemoglobin is combined with O2, we have \([H \cdot O_{2}] = 0.88[H]_0\).
03

Substitute the concentrations in the equilibrium expression

Substitute the expressions for \([H \cdot CO]\) and \([H \cdot O_{2}]\) into the equilibrium expression, obtaining: $$K = \frac{0.12[H]_0[O_{2}]}{0.88[H]_0[CO]}$$
04

Simplify the expression and solve for the partial pressure ratio

We can cancel out the \([H]_0\) from the numerator and denominator, and we get: $$K = \frac{0.12[O_{2}]}{0.88[CO]}$$ Now, solve for \(P_{\mathrm{Co}} / P_{\mathrm{O}_{2}}\), which is equivalent to \([CO]/[O_{2}]\). Note that this is equivalent because the partial pressure of a gas is proportional to its concentration: $$\frac{[CO]}{[O_{2}]} = \frac{0.12[O_{2}]}{0.88K}$$ Substitute the given value of K: $$\frac{[CO]}{[O_{2}]} = \frac{0.12[O_{2}]}{0.88(2.0 \times 10^{2})}$$
05

Finalize the answer

Simplify the expression to obtain the ratio of partial pressures: $$\frac{P_{\mathrm{Co}}}{P_{\mathrm{O}_{2}}} = \frac{0.12}{0.88(2.0 \times 10^{2})} = 7.6 \times 10^{-4}$$ Thus, the required ratio of \(P_{\mathrm{Co}} / P_{\mathrm{O}_{2}}\) is approximately \(7.6 \times 10^{-4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant, represented as K, is a fundamental concept in chemistry, conveying the ratio of concentrations of products to reactants at equilibrium. It’s crucial to understand that K is constant only at a particular temperature and it reflects the relative concentration of the substances involved in a reversible chemical reaction when it is no longer changing – a state known as chemical equilibrium.

In the context of the problem, the equilibrium expression for the reaction between hemoglobin, oxygen, and carbon monoxide is defined as
\t$$K = \frac{[H \cdot CO][O_{2}]}{[H \cdot O_{2}][CO]}$$
\t where square brackets denote concentrations. This equation indicates that the product of the concentrations of hemoglobin bound to carbon monoxide and oxygen gas divided by the product of the concentrations of hemoglobin bound to oxygen (in its aquatic form) and carbon monoxide gas is constant at equilibrium.

It is essential to understand that the equilibrium constant tells us the extent of a reaction; a large K value suggests that the reaction tends to produce more products, whereas a small K value indicates a reaction that favors the reactants. In the given exercise, by using the value of K and the percentage of hemoglobin converted, we can calculate the desired ratio of partial pressures.
Hemoglobin Binding
Hemoglobin is a protein found in red blood cells that is crucial for transporting oxygen from the lungs to tissues throughout the body. It can bind to various gases, including oxygen (O2) and carbon monoxide (CO). Hemoglobin's binding to these gases is reversible, allowing it to pick up and release oxygen efficiently. However, the binding of these gases is also competitive, meaning high concentrations of CO can prevent O2 from binding to hemoglobin.

Understanding the competitive nature of hemoglobin binding is vital, particularly in cases of CO poisoning, where CO outcompetes O2 for the same binding sites on hemoglobin. In the provided problem, the hemoglobin binding dynamics are represented in the equilibrium reaction, and we are asked to determine the influence of gas partial pressures on this competition.

In our case, since 12% of hemoglobin has bound to CO, which is a significant amount given the affinity hemoglobin has for CO, it implies that there must be defined conditions – dictated by the equilibrium constant and partial pressures – where this percentage is stable. By calculating the ratio of partial pressures, we can infer the environmental conditions conducive to this level of hemoglobin conversion.
Gas Partial Pressure
Gas partial pressure is a concept in chemistry that describes the pressure a single gas in a mixture of gases would exert if it alone occupied the entire volume of the mixture. Dalton’s Law of Partial Pressures states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas.

The partial pressure of a gas is directly proportional to its concentration, meaning that a higher partial pressure corresponds to a higher concentration of that gas. In biological systems, like the human body, the partial pressure of oxygen and carbon monoxide significantly affects the binding of these gases to hemoglobin.

For instance, in the exercise, we use this proportional relationship to equate the ratio of gas concentrations to the ratio of their partial pressures to solve for the needed ratio of partial pressures given the equilibrium condition. By understanding the interplay between gas partial pressure and hemoglobin binding, one can comprehend the delicate balance necessary for proper bodily function, such as the transport of oxygen throughout the body.

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Most popular questions from this chapter

Consider three complexes of \(\mathrm{Ag}^{+}\) and their formation constants, \(K_{\mathrm{f}}\) $$\begin{array}{ll}\hline \text { Complex lon } & K_{\mathrm{f}} \\\\\hline \mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}+ & 1.6 \times 10^{7} \\ \mathrm{Ag}(\mathrm{CN})_{2}^{-} & 5.6 \times 10^{18} \\\\\mathrm{AgBr}_{2}^{-} & 1.3 \times 10^{7} \\ \hline\end{array}$$ Which statements are true? (a) \(\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}{ }^{+}\) is more stable than \(\mathrm{Ag}(\mathrm{CN})_{2}^{-}\). (b) Adding a strong acid \(\left(\mathrm{HNO}_{3}\right)\) to a solution that is \(0.010 \mathrm{M}\) in \(\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}^{+}\) will tend to dissociate the complex ion into \(\mathrm{Ag}^{+}\) and \(\mathrm{NH}_{4}^{+} .\) (c) Adding a strong acid \(\left(\mathrm{HNO}_{3}\right)\) to a solution that is \(0.010 \mathrm{M}\) in \(\mathrm{AgBr}_{2}^{-}\) will tend to dissociate the complex ion into \(\mathrm{Ag}^{+}\) and \(\mathrm{Br}^{-} .\) (d) To dissolve AgI, one can add either \(\mathrm{NaCN}\) or \(\mathrm{HCN}\) as a source of the cyanide-complexing ligand. Fewer moles of NaCN would be required. (e) Solution \(A\) is \(0.10 M\) in \(B r^{-}\) and contains the complex ion \(\mathrm{AgBr}_{2}^{-}\). Solution B is \(0.10 M\) in \(\mathrm{CN}^{-}\) and contains the complex ion \(\mathrm{Ag}(\mathrm{CN})_{2}-\). Solution B will have more particles of complex ion per particle of \(\mathrm{Ag}^{+}\) than solution \(\mathrm{A}\).

A child eats \(10.0 \mathrm{~g}\) of paint containing \(5.0 \% \mathrm{~Pb}\). How many grams of the sodium salt of EDTA, \(\mathrm{Na}_{4}(\mathrm{EDTA})\), should he receive to bring the lead into solution as \(\mathrm{Pb}\). EDTA?

Sketch the geometry of (a) \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\) (tetrahedral) (b) cis \(-\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right]^{+}\) (c) trans- \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Br}_{2}\right]^{2+}\) (d) trans- \(\left[\mathrm{Ni}(\mathrm{ox})_{2}(\mathrm{OH})_{2}\right]^{3-}\) (e) \([\mathrm{Au}(\mathrm{CN}) \mathrm{Br}]^{+}\)

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Consider the complex ion \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2} \mathrm{Cl}_{2}(\mathrm{OH})_{2}\right]^{2-}\). (a) Identify the ligands and their charges. (b) What is the oxidation number of nickel? (c) What is the formula for the sodium salt of this ion?

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