For the following half-reactions, answer the questions below. $$ \begin{array}{cc} \mathrm{Co}^{3+}(a q)+e^{-} \longrightarrow \mathrm{Co}^{2+}(a q) & E^{\circ}=+1.953 \mathrm{~V} \\ \mathrm{Fe}^{3+}(a q)+e^{-} \longrightarrow \mathrm{Fe}^{2+}(a q) & E^{\circ}=+0.769 \mathrm{~V} \\ \mathrm{I}_{2}(a q)+2 e^{-} \longrightarrow 2 \mathrm{I}^{-}(a q) & E^{o}=+0.534 \mathrm{~V} \\ \mathrm{~Pb}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Pb}(s) & E^{\circ}=-0.127 \mathrm{~V} \\ \mathrm{Cd}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Cd}(s) & E^{\circ}=-0.402 \mathrm{~V} \\ \mathrm{Mn}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Mn}(s) & E^{\circ}=-1.182 \mathrm{~V} \end{array} $$ (a) Which is the weakest reducing agent? (b) Which is the strongest reducing agent? (c) Which is the strongest oxidizing agent? (d) Which is the weakest oxidizing agent? (e) Will \(\mathrm{Pb}(s)\) reduce \(\mathrm{Fe}^{3+}(a q)\) to \(\mathrm{Fe}^{2+}(a q) ?\) (f) Will \(\mathrm{I}^{-}(a q)\) reduce \(\mathrm{Pb}^{2+}(a q)\) to \(\mathrm{Pb}(s) ?\) (g) Which ion(s) can be reduced by \(\mathrm{Pb}(s)\) ? (h) Which if any metal(s) can be oxidized by \(\mathrm{Fe}^{3+}(a q)\) ?

Short Answer

Expert verified
Answer: Co^3+(aq) is the weakest reducing agent.

Step by step solution

01

(a) Weakest reducing agent

The weakest reducing agent will have the highest standard reduction potential. In this case, Co redution potential is +1.953 V, which is the highest among the given half-reactions. Therefore, Co^3+(aq) is the weakest reducing agent.
02

(b) Strongest reducing agent

The strongest reducing agent will have the lowest standard reduction potential. In this case, Mn's reduction potential is -1.182 V, which is the lowest among the given half-reactions. Therefore, Mn^2+(aq) is the strongest reducing agent.
03

(c) Strongest oxidizing agent

The strongest oxidizing agent will have the highest standard reduction potential. As determined in part (a), it is the Co^3+(aq) with a standard reduction potential of +1.953 V.
04

(d) Weakest oxidizing agent

The weakest oxidizing agent will have the lowest standard reduction potential. As determined in part (b), it is the Mn^2+(aq) with a standard reduction potential of -1.182 V.
05

(e) Will Pb(s) reduce Fe^3+(aq) to Fe^2+(aq)?

To determine if Pb(s) will spontaneously reduce Fe^3+(aq) to Fe^2+(aq), compare the standard reduction potentials of both half-reactions. Pb's reduction potential is -0.127 V, while Fe^3+'s is +0.769 V. Since Pb's potential is lower than Fe^3+'s, Pb(s) will spontaneously reduce Fe^3+(aq) to Fe^2+(aq).
06

(f) Will I^-(aq) reduce Pb^2+(aq) to Pb(s)?

In order to determine if I^-(aq) will spontaneously reduce Pb^2+(aq) to Pb(s), compare the standard reduction potentials of both half-reactions. I₂ reduction potential is +0.534 V, while Pb^2+'s is -0.127 V. Since I₂'s potential is higher than Pb^2+'s, I^-(aq) will not spontaneously reduce Pb^2+(aq) to Pb(s).
07

(g) Which ions can be reduced by Pb(s)?

To determine which ions can be reduced by Pb(s), compare Pb's standard reduction potential (-0.127 V) with other ions. Pb(s) can reduce ions with a higher reduction potential, which includes: Fe^3+(aq) with a potential of +0.769 V and Co^3+(aq) with a potential of +1.953 V.
08

(h) Which metals can be oxidized by Fe^3+(aq)?

To determine which metals can be oxidized by Fe^3+(aq), compare its standard reduction potential (+0.769 V) with other metals. Fe^3+(aq) can oxidize metals with a lower reduction potential, which includes: Pb(s) with a potential of -0.127 V, Cd(s) with a potential of -0.402 V, and Mn(s) with a potential of -1.182 V.

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Most popular questions from this chapter

Which of the following reactions is (are) spontaneous at standard conditions? (a) \(2 \mathrm{NO}_{3}^{-}(a q)+8 \mathrm{H}^{+}(a q)+6 \mathrm{Cl}^{-}(a q) \longrightarrow\) \(2 \mathrm{NO}(g)+4 \mathrm{H}_{2} \mathrm{O}+3 \mathrm{Cl}_{2}(g)\) (b) \(\mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q)+4 \mathrm{Cl}^{-}(a q) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{Cl}_{2}(g)\) (c) \(3 \mathrm{Fe}(s)+2 \mathrm{AuCl}_{4}^{-}(a q) \longrightarrow 2 \mathrm{Au}(s)+8 \mathrm{Cl}^{-}(a q)+3 \mathrm{Fe}^{2+}(a q)\)

Consider three metals, \(\mathrm{X}, \mathrm{Y}\), and \(\mathrm{Z}\), and their salts, \(\mathrm{XA}, \mathrm{YA}\), and \(\mathrm{ZA}\). Three experiments take place with the following results: \- \(\mathrm{X}+\mathrm{hot} \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{2}\) bubbles \(\mathrm{X}+\mathrm{YA} \longrightarrow\) no reaction I \(\mathrm{X}+\mathrm{ZA} \longrightarrow \mathrm{X}\) discolored \(+\mathrm{Z}\) Rank metals \(\mathrm{X}, \mathrm{Y}\), and \(\mathrm{Z}\), in order of decreasing strength as reducing agents.

Which species in each pair is the stronger oxidizing agent? (a) \(\mathrm{NO}_{3}^{-}\) or \(\mathrm{I}_{2}\) (b) \(\mathrm{Fe}(\mathrm{OH})_{3}\) or \(\mathrm{S}\) (c) \(\mathrm{Mn}^{2+}\) or \(\mathrm{MnO}_{2}\) (d) \(\mathrm{ClO}_{3}^{-}\) in acidic solution or \(\mathrm{ClO}_{3}^{-}\) in basic solution

Consider a voltaic cell in which the following reaction occurs. $$ \mathrm{Zn}(s)+\mathrm{Sn}^{2+}(a q) \longrightarrow \mathrm{Zn}^{2+}(a q)+\mathrm{Sn}(s) $$ (a) Calculate \(E^{\circ}\) for the cell. (b) When the cell operates, what happens to the concentration of \(\mathrm{Zn}^{2+}\) ? The concentration of \(\mathrm{Sn}^{2+}\) ? (c) When the cell voltage drops to zero, what is the ratio of the concentration of \(\mathrm{Zn}^{2+}\) to that of \(\mathrm{Sn}^{2+}\) ? (d) If the concentration of both cations is \(1.0 \mathrm{M}\) originally, what are the concentrations when the voltage drops to zero?

Use the following half-equations to write three spontaneous reactions. Justify your answers by calculating \(E^{\circ}\) for the cells. (1) \(\mathrm{MnO}_{4}^{-}(a q)+8 \mathrm{H}^{+}(a q)+5 e^{-} \longrightarrow \mathrm{Mn}^{2+}(a q)+4 \mathrm{H}_{2} \mathrm{O}\) \(E^{\circ}=+1.512 \mathrm{~V}\) (2) \(\mathrm{O}_{2}(\mathrm{~g})+4 \mathrm{H}^{+}(\mathrm{aq})+4 e^{-} \longrightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad E^{\circ}=+1.229 \mathrm{~V}\) (3) \(\mathrm{Co}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Co}(s) \quad E^{\circ}=-0.282 \mathrm{~V}\)

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