Chapter 18: Problem 35
Which of the following species will react with \(1 \mathrm{M} \mathrm{HNO}_{3}\) ? (a) \(\mathrm{I}^{-}\) (b) Fe (c) \(\mathrm{Ag}\) (d) \(\mathrm{Pb}\)
Short Answer
Expert verified
(a) I⁻, (b) Fe, (c) Ag, (d) Pb.
Answer: (b) Fe and (d) Pb.
Step by step solution
01
Write the half-reactions for the given species
The half-reactions for the given species are:
(a) \(\mathrm{I}^{-}(aq) \rightarrow \mathrm{I}_{2}(s) + 2 e^{-}\)
(b) \(\mathrm{Fe}(s) \rightarrow \mathrm{Fe}^{2+}(aq) + 2 e^{-}\)
(c) \(\mathrm{Ag}(s) \rightarrow \mathrm{Ag}^{+}(aq) + e^{-}\)
(d) \(\mathrm{Pb}(s) \rightarrow \mathrm{Pb}^{2+}(aq) + 2 e^{-}\)
02
Determine the standard reduction potentials for each species
Using the standard reduction potential table, we can find the values for the given species as follows:
(a) \(\mathrm{I}^{-}(aq) \rightarrow \mathrm{I}_{2}(s) + 2 e^{-}\), E° = +0.54 V
(b) \(\mathrm{Fe}(s) \rightarrow \mathrm{Fe}^{2+}(aq) + 2 e^{-}\), E° = -0.44 V
(c) \(\mathrm{Ag}(s) \rightarrow \mathrm{Ag}^{+}(aq) + e^{-}\), E° = +0.80 V
(d) \(\mathrm{Pb}(s) \rightarrow \mathrm{Pb}^{2+}(aq) + 2 e^{-}\), E° = -0.13 V
For \(\mathrm{HNO}_3\), the standard reduction potential is:
\(\mathrm{NO_3^{-}}(aq) + 4 \mathrm{H}^{+}(aq) + 3 e^{-} \rightarrow \mathrm{NO}(g) + 2 \mathrm{H_2}O(l)\), E° = +0.96 V
03
Compare the standard reduction potentials with that of \(\mathrm{HNO}_3\)
To determine which species will react with \(\mathrm{HNO}_3\), we must compare the standard reduction potentials of the given species to that of \(\mathrm{HNO}_3\). A reaction is favorable if the standard reduction potential of the given species is lower than the standard reduction potential of \(\mathrm{HNO}_3\):
(a) E°(+0.54 V) > E°(\(\mathrm{HNO}_3\))
(b) E°(-0.44 V) < E°(\(\mathrm{HNO}_3\))
(c) E°(+0.80 V) > E°(\(\mathrm{HNO}_3\))
(d) E°(-0.13 V) < E°(\(\mathrm{HNO}_3\))
04
Identify which species will react with \(\mathrm{HNO}_3\)
According to the comparison in Step 3, it can be seen that species (b) Fe and (d) \(\mathrm{Pb}\) have lower standard reduction potentials than \(\mathrm{HNO}_3\). Therefore, these species will react with \(1 \mathrm{M} \mathrm{HNO}_{3}\):
(b) Fe
(d) \(\mathrm{Pb}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrochemistry
Electrochemistry is a branch of chemistry that studies the movement of electrons and the conversion of energy between electrical form and chemical form. This field is essential for understanding how batteries work, the principles behind corrosion, and the mechanisms of certain types of sensors. At the heart of electrochemistry is the concept of redox or reduction-oxidation reactions, where one species gains electrons (reduction) and another species loses electrons (oxidation).
One fundamental aspect of electrochemistry is the standard reduction potential, which is a measure of the tendency of a chemical species to acquire electrons and be reduced. Each half-reaction in an electrochemical cell has a standard reduction potential, which can be found in tables and is measured in volts. The standard reduction potential reflects a species' affinity for electrons; a positive value indicates a greater willingness to be reduced. In the exercise, comparing standard reduction potentials provided insights into which substances would react with 1M HNO3 based on their respective tendencies to gain or lose electrons.
One fundamental aspect of electrochemistry is the standard reduction potential, which is a measure of the tendency of a chemical species to acquire electrons and be reduced. Each half-reaction in an electrochemical cell has a standard reduction potential, which can be found in tables and is measured in volts. The standard reduction potential reflects a species' affinity for electrons; a positive value indicates a greater willingness to be reduced. In the exercise, comparing standard reduction potentials provided insights into which substances would react with 1M HNO3 based on their respective tendencies to gain or lose electrons.