Atomic masses can be determined by electrolysis. In one hour, a current of \(0.600\) A deposits \(2.42 \mathrm{~g}\) of a certain metal, \(\mathrm{M}\), which is present in solution as \(\mathrm{M}^{+}\) ions. What is the atomic mass of the metal?

Short Answer

Expert verified
Answer: The atomic mass of the metal is approximately 108 g/mol.

Step by step solution

01

Determine the electric charge passed

The first step is to calculate the total electric charge passed during electrolysis. Electric charge (Q) can be calculated using the formula: $$Q = It$$ where \(I\) is the current and \(t\) is the time (in seconds). The given current, \(I\), is 0.600 A and the time, \(t\), is 1 hour (which is equivalent to 3600 seconds). To find the charge, we just need to multiply these values: $$Q = (0.600 A)(3600 s) = 2160 C$$
02

Calculate the moles of the metal ions deposited

The second step is to calculate the moles of metal ions deposited during the electrolysis process. We will use Faraday's law of electrolysis to determine this: $$\text{moles of ions} = \frac{\text{charge}}{\text{Faraday's constant} \times \text{number of electrons per ion}}$$ We are given that the metal's ions have a charge of +1 (as \(\mathrm{M}^{+}\) ions), so the number of electrons per ion would also be 1. Faraday's constant is approximately \(9.65 \times 10^{4} \mathrm{C/mol}\). Now we can calculate the moles of ions deposited: $$\text{moles of ions} = \frac{2160 C}{(9.65 \times 10^{4} \mathrm{C/mol}) \times 1} \approx 0.0224 \mathrm{moles}$$
03

Calculate the atomic mass of the metal

Finally, we will determine the atomic mass of the metal using the relationship between moles, mass, and atomic mass: $$\text{atomic mass} = \frac{\text{mass}}{\text{moles}}$$ We are given that the mass of the metal deposited is 2.42 g. Now we can find the atomic mass of the metal: $$\text{atomic mass} = \frac{2.42 g}{0.0224 \mathrm{moles}} \approx 108 \mathrm{g/mol}$$ So the atomic mass of the metal is approximately 108 g/mol.

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