A scintillation counter registers emitted radiation caused by the disintegration of nuclides. If each atom of nuclide emits one count, what is the activity of a sample that registers \(3.00 \times 10^{4}\) disintegrations in five minutes?

Short Answer

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Question: Calculate the activity of a sample that has 3.00 x 10^4 disintegrations in 5 minutes. Answer: The activity of the sample is 100 Becquerel (Bq).

Step by step solution

01

Convert time from minutes to seconds

Time is given in minutes, so we will first convert it into seconds. 1 minute = 60 seconds 5 minutes = 5 * 60 = 300 seconds. Now that we have the time in seconds, we can proceed to calculate the activity.
02

Calculate activity

The activity (A) can be calculated using the formula: Activity (A) = number of disintegrations (N) / time period (t) Given the number of disintegrations (N = 3.00 x 10^4) and the time period (t = 300 seconds), we can calculate the activity by plugging the values into the formula: A = (3.00 × 10^4) disintegrations / 300 seconds A = (3.00 × 10^4) / 300
03

Calculate the result

Now, we can use a calculator to find the result: A = (3.00 × 10^4) / 300 A = 100 Bq The activity of the sample is 100 Becquerel (Bq).

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