Complete and balance the following equations. If no reaction occurs, write NR. (a) \(\mathrm{Cl}_{2}(g)+\mathrm{I}^{-}(a q) \longrightarrow\) (b) \(\mathrm{F}_{2}(g)+\mathrm{Br}^{-}(a q) \longrightarrow\) (c) \(\mathrm{I}_{2}(s)+\mathrm{Cl}^{-}(a q) \longrightarrow\) (d) \(\mathrm{Br}_{2}(l)+\mathrm{I}^{-}(a q) \longrightarrow\)

Short Answer

Expert verified
(a) Cl2(g) + I⁻(aq) (b) F2(g) + Br⁻(aq) (c) I2(s) + Cl⁻(aq) (d) Br2(l) + I⁻(aq) Answer: (a) Yes, the reaction will occur. The balanced chemical equation is: Cl₂(g) + 2I⁻(aq) ⟶ 2Cl⁻(aq) + I₂(s) (b) Yes, the reaction will occur. The balanced chemical equation is: F₂(g) + 2Br⁻(aq) ⟶ 2F⁻(aq) + Br₂(l) (c) No, the reaction will not occur. (d) Yes, the reaction will occur. The balanced chemical equation is: Br₂(l) + 2I⁻(aq) ⟶ 2Br⁻(aq) + I₂(s)

Step by step solution

01

Use the activity series to determine possible reactions

For each of the given equations (a) to (d), we will use the activity series of halogens mentioned above to determine whether a halogen can replace another halogen in the compound.
02

(a) Determine the reaction for Cl2(g) + I⁻(aq)

Chlorine (Cl₂) is higher in the activity series than Iodine (I₂) and therefore can replace Iodine in the compound. So a reaction will occur.
03

(a) Complete and balance the reaction for Cl2(g) + I⁻(aq)

Cl₂(g) + 2I⁻(aq) ⟶ 2Cl⁻(aq) + I₂(s)
04

(b) Determine the reaction for F2(g) + Br⁻(aq)

Fluorine (F₂) is higher in the activity series than Bromine (Br₂) and therefore can replace Bromine in the compound. So a reaction will occur.
05

(b) Complete and balance the reaction for F2(g) + Br⁻(aq)

F₂(g) + 2Br⁻(aq) ⟶ 2F⁻(aq) + Br₂(l)
06

(c) Determine the reaction for I2(s) + Cl⁻(aq)

Iodine (I₂) is lower in the activity series than Chlorine (Cl₂) and therefore cannot replace Chlorine in the compound. So no reaction will occur.
07

(c) Write NR for no reaction

I₂(s) + Cl⁻(aq) ⟶ NR
08

(d) Determine the reaction for Br2(l) + I⁻(aq)

Bromine (Br₂) is higher in the activity series than Iodine (I₂) and therefore can replace Iodine in the compound. So a reaction will occur.
09

(d) Complete and balance the reaction for Br2(l) + I⁻(aq)

Br₂(l) + 2I⁻(aq) ⟶ 2Br⁻(aq) + I₂(s) The solutions for the given reactions are: (a) Cl₂(g) + 2I⁻(aq) ⟶ 2Cl⁻(aq) + I₂(s) (b) F₂(g) + 2Br⁻(aq) ⟶ 2F⁻(aq) + Br₂(l) (c) I₂(s) + Cl⁻(aq) ⟶ NR (d) Br₂(l) + 2I⁻(aq) ⟶ 2Br⁻(aq) + I₂(s)

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