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Chapter 22: Problem 10

Follow the directions of Problem 9 for the following names. (a) 2, 2-dimethylbutane (b) 4 -methylpentane (c) 2-ethylpropane

Short Answer

Expert verified
Question: Draw the structural formulas for the following alkanes: (a) 2,2-Dimethylbutane (b) 4-Methylpentane (c) 2-Ethylpropane. Answer: (a) 2,2-Dimethylbutane: CH3 | CH3-CH-C-CH2-CH3 | CH3 (b) 4-Methylpentane: CH3-CH2-CH2-CH-C-CH3 | CH3 (c) 2-Ethylpropane: CH2-CH3 | CH3-CH-C-CH3 | CH3

Step by step solution

01

(a) 2,2-Dimethylbutane)

(First, identify the main carbon chain in the name, which is butane. Butane consists of a 4-carbon chain, represented as C-C-C-C. Next, find the branching group(s), which are 2 methyl groups (CH3) in this case. The numbers in the name, 2,2, represent the positions of the two methyl groups on the main carbon chain. Now, draw the structural formula by attaching the two methyl groups at the second carbon in the butane chain. The resulting structure should look like this: CH3 | CH3-CH-C-CH2-CH3 | CH3)
02

(b) 4-Methylpentane)

(First, identify the main carbon chain in the name, which is pentane. Pentane consists of a 5-carbon chain, represented as C-C-C-C-C. Next, find the branching group, which is a methyl group (CH3) in this case. The number 4 in the name represents the position of the methyl group on the main carbon chain. Now, draw the structural formula by attaching the methyl group at the fourth carbon in the pentane chain. The resulting structure should look like this: CH3-CH2-CH2-CH-C-CH3 | CH3)
03

(c) 2-Ethylpropane)

(First, identify the main carbon chain in the name, which is propane. Propane consists of a 3-carbon chain, represented as CH3-CH2-CH3. Next, find the branching group, which is an ethyl group (CH2CH3) in this case. The number 2 in the name represents the position of the ethyl group on the main carbon chain. Now, draw the structural formula by attaching the ethyl group at the second carbon in the propane chain. The resulting structure should look like this: CH2-CH3 | CH3-CH-C-CH3 | CH3)

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Most popular questions from this chapter

16\. Classify each of the following as a carboxylic acid, ester, and/or alcohol. (a) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{OH}\)

Writean equation for the reaction of chloroaceticacid \(\left(K_{\mathrm{a}}=1.5 \times 10^{-3}\right)\) with trimethylamine \(\left(K_{\mathrm{b}}=5.9 \times 10^{-5}\right) .\) Calculate the equilibrium constant for the reaction. If \(0.10 M\) solutions of these two species are mixed, what will be their concentrations at equilibrium?

R For which of the following is geometric isomerism possible? (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CCl}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm{ClC}=\mathrm{CCH}_{3} \mathrm{Cl}\) (c) \(\mathrm{CH}_{3} \mathrm{BrC}=\mathrm{CCH}_{3} \mathrm{Cl}\)

The \(K_{\mathrm{b}}\) for ethylamine \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\right)\) is \(4.3 \times 10^{-4}\). What is the \(\mathrm{pH}\) of a \(0.250 \mathrm{M}\) solution of ethylamine? Compare with the \(\mathrm{pH}\) of a \(0.250 \mathrm{M}\) solution of ammonia \(\left(K_{b}=1.86 \times 10^{-5}\right)\).

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