Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 22: Problem 18

In each of the following, name the functional group (i.e., ester, aldehyde,....). (a) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{O}-\mathrm{CH}_{3}\)

Short Answer

Expert verified
Answer: Ether

Step by step solution

01

Identify the functional group

Find the unique bond or arrangement of atoms in the compound. For the given molecule, we can see there is a bond between a carbon atom and an oxygen atom: C-O-C.
02

Determine if the functional group is an ester, aldehyde, or another type of functional group

Now that we have identified the C-O-C structure, we need to find out what type of functional group it represents. The structure has an oxygen atom single bonded to two carbon atoms. This oxygen atom bridges the carbon atoms, we know the functional group must be an ether.
03

Provide the answer

The functional group in the given compound, \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{O}-\mathrm{CH}_{3}\), is an ether.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Follow the directions of Problem 9 for the following names. (a) 2, 2-dimethylbutane (b) 4 -methylpentane (c) 2-ethylpropane

16\. Classify each of the following as a carboxylic acid, ester, and/or alcohol. (a) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{OH}\)

Writean equation for the reaction of chloroaceticacid \(\left(K_{\mathrm{a}}=1.5 \times 10^{-3}\right)\) with trimethylamine \(\left(K_{\mathrm{b}}=5.9 \times 10^{-5}\right) .\) Calculate the equilibrium constant for the reaction. If \(0.10 M\) solutions of these two species are mixed, what will be their concentrations at equilibrium?

There are three compounds with the formula \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Cl}_{3}\) in which three of the hydrogen atoms of the benzene molecule have been replaced by chlorine atoms. Draw structures for these compounds.

Give the structure of (a) a three-carbon alcohol with the -OH group on the center carbon. (b) a four-carbon branched-chain carboxylic acid. (c) the ester formed when these two compounds react.
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Organic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free