Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 22: Problem 2

Classify each of the following hydrocarbons as alkanes, alkenes, or alkynes. (a) \(\mathrm{C}_{12} \mathrm{H}_{24}\) (b) \(\mathrm{C}_{7} \mathrm{H}_{12}\) (c) \(\mathrm{C}_{13} \mathrm{H}_{28}\)

Short Answer

Expert verified
Question: Classify the following hydrocarbons as alkanes, alkenes, or alkynes: (a) \(\mathrm{C}_{12} \mathrm{H}_{24}\), (b) \(\mathrm{C}_{7} \mathrm{H}_{12}\), and (c) \(\mathrm{C}_{13} \mathrm{H}_{28}\). Answer: (a) \(\mathrm{C}_{12} \mathrm{H}_{24}\) is an alkene, (b) \(\mathrm{C}_{7} \mathrm{H}_{12}\) is an alkyne, and (c) \(\mathrm{C}_{13} \mathrm{H}_{28}\) is an alkane.

Step by step solution

01

Classifying Hydrocarbon (a) \(\mathrm{C}_{12} \mathrm{H}_{24}\)

First, we'll compare the given hydrocarbon to the general formulas: 1. Alkane: \(\mathrm{C}_{12}\mathrm{H}_{2(12)+2}=\mathrm{C}_{12}\mathrm{H}_{26}\) 2. Alkene: \(\mathrm{C}_{12}\mathrm{H}_{2(12)}=\mathrm{C}_{12}\mathrm{H}_{24}\) 3. Alkyne: \(\mathrm{C}_{12}\mathrm{H}_{2(12)-2}=\mathrm{C}_{12}\mathrm{H}_{22}\) Since the given hydrocarbon matches the alkene formula, we can classify \(\mathrm{C}_{12} \mathrm{H}_{24}\) as an alkene.
02

Classifying Hydrocarbon (b) \(\mathrm{C}_{7} \mathrm{H}_{12}\)

Next, we'll compare this hydrocarbon to the general formulas: 1. Alkane: \(\mathrm{C}_{7}\mathrm{H}_{2(7)+2}=\mathrm{C}_{7}\mathrm{H}_{16}\) 2. Alkene: \(\mathrm{C}_{7}\mathrm{H}_{2(7)}=\mathrm{C}_{7}\mathrm{H}_{14}\) 3. Alkyne: \(\mathrm{C}_{7}\mathrm{H}_{2(7)-2}=\mathrm{C}_{7}\mathrm{H}_{12}\) Since the given hydrocarbon matches the alkyne formula, we can classify \(\mathrm{C}_{7} \mathrm{H}_{12}\) as an alkyne.
03

Classifying Hydrocarbon (c) \(\mathrm{C}_{13} \mathrm{H}_{28}\)

Finally, we'll compare this hydrocarbon to the general formulas: 1. Alkane: \(\mathrm{C}_{13}\mathrm{H}_{2(13)+2}=\mathrm{C}_{13}\mathrm{H}_{28}\) 2. Alkene: \(\mathrm{C}_{13}\mathrm{H}_{2(13)}=\mathrm{C}_{13}\mathrm{H}_{26}\) 3. Alkyne: \(\mathrm{C}_{13}\mathrm{H}_{2(13)-2}=\mathrm{C}_{13}\mathrm{H}_{24}\) Since the given hydrocarbon matches the alkane formula, we can classify \(\mathrm{C}_{13} \mathrm{H}_{28}\) as an alkane.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When aniline, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\left(K_{\mathrm{b}}=7.4 \times 10^{-10}\right)\), reacts with a strong acid, its conjugate acid, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\), is formed. Calculate the \(\mathrm{pH}\) of a \(0.100 \mathrm{M}\) solution of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\) and compare it with the \(\mathrm{pH}\) of acetic acid \(\left(K_{\mathrm{a}}=\right.\) \(\left.1.86 \times 10^{-5}\right)\)

Write the structural formulas of all the esters that can be formed by ethylene glycol with formic and acetic acids. (One or both of the - OH groups of ethylene glycol can react.)

There are three compounds with the formula \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Cl}_{3}\) in which three of the hydrogen atoms of the benzene molecule have been replaced by chlorine atoms. Draw structures for these compounds.

Draw structures for all the saturated carboxylic acids with four carbon atoms per molecule.

Write the formula for (a) an alkyne with 16 hydrogen atoms. (b) an alkene with 44 hydrogen atoms. (c) an alkane with ten carbon atoms.
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free