Chapter 23: Problem 6
Show the structure of the monomer used to make the following addition polymers.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 23: Problem 6
Show the structure of the monomer used to make the following addition polymers.
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeA \(1.00\) -mg sample of a pare protein yielded on hydrolysis \(0.0165 \mathrm{mg}\) of leucine and \(0.0248 \mathrm{mg}\) of isoleucine. What is the minimum possible molar mass of the protein? (MM leucine \(=\) MM isoleucine \(=131 \mathrm{~g} / \mathrm{mol}\) )
Describe what is meant by (a) the primary structure of a protein. (b) the secondary structure of a protein. (c) the tertiary structure of a protein.
WEB A tripeptide contains valine, lysine, and phenylalanine residues. (a) How many tripeptides are possible from these amino acids? (b) Draw a structural formula for a possible form of the tripeptide and name it, using the shorthand form.
Sketch the tetrapeptide obtained from four molecules of the \(\alpha\) -amino acid glycine.
Gycolysis is the process by which glucose is metabolized to lactic acid according to the equation $$ \begin{gathered} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q) \longrightarrow 2 \mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{3}(a q) \\ \Delta G^{6}=-198 \mathrm{~kJ} \text { at } \mathrm{pH} 7.0 \text { and } 25^{\circ} \mathrm{C} \end{gathered} $$ Glycolysis is the source of energy in human red blood cells. In these cells, the concentration of glucose is \(5.0 \times 10^{-3} M_{3}\) while that of lactic acid is \(2.9 \times 10^{-3} M\). Calculate \(\Delta G\) for glycolysis in human blood cells under these conditions. Use the equation \(\Delta G=\Delta G^{\circ}+\mathrm{RT} \ln Q\), where \(Q\) is the concentration quotient, analogous to \(K\).
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