Convert the following to moles. (a) \(35.00 \mathrm{~g}\) of \(\mathrm{CF}_{2} \mathrm{Cl}_{2}\), a chlorofluorocarbon that destroys the ozone layer in the atmosphere (b) \(100.0 \mathrm{mg}\) of iron(II) sulfate, an iron supplement prescribed for anemia (c) \(2.00 \mathrm{~g}\) of Valium \(\left(\mathrm{C}_{15} \mathrm{H}_{13} \mathrm{ClN}_{2} \mathrm{O}-\right.\) diazepam \()\)

Short Answer

Expert verified
Question: Calculate the number of moles for each of the following substances: (a) 35.00 g of CF2Cl2, (b) 32.00 mg of iron(II) sulfate (FeSO4), and (c) 2.00 g of diazepam (C15H13ClN2O).

Step by step solution

01

Find the molar mass of CF2Cl2

Find the molar mass of each element in the formula using the periodic table: C = 12.01 g/mol, F = 19.00 g/mol, and Cl = 35.45 g/mol. Then calculate the molar mass of CF2Cl2 using the formula: Molar mass = (1 x C) + (2 x F) + (2 x Cl)
02

Calculate the moles of CF2Cl2

Use the molar mass and the given mass of CF2Cl2 to calculate the number of moles: Number of moles = (35.00 g) / (Molar mass of CF2Cl2) #(b):#
03

Find the molar mass of FeSO4

Find the molar mass of each element in the formula using the periodic table: Fe = 55.85 g/mol, S = 32.07 g/mol, and O = 16.00 g/mol. Then calculate the molar mass of FeSO4 using the formula: Molar mass = (1 x Fe) + (1 x S) + (4 x O)
04

Convert mg to g

We need to convert the mass of iron(II) sulfate from mg to g. We can do this using the conversion factor: 1 g = 1000 mg
05

Calculate the moles of FeSO4

Use the molar mass and the given mass of FeSO4 to calculate the number of moles: Number of moles = (mass in g) / (Molar mass of FeSO4) #(c):#
06

Find the molar mass of C15H13ClN2O

Find the molar mass of each element in the formula using the periodic table: C = 12.01 g/mol, H = 1.01 g/mol, Cl = 35.45 g/mol, N = 14.01 g/mol, and O = 16.00 g/mol. Then calculate the molar mass of C15H13ClN2O using the formula: Molar mass = (15 x C) + (13 x H) + (1 x Cl) + (2 x N) + (1 x O)
07

Calculate the moles of C15H13ClN2O

Use the molar mass and the given mass of diazepam to calculate the number of moles: Number of moles = (2.00 g) / (Molar mass of C15H13ClN2O)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
The concept of molar mass is central to chemistry and is particularly important when it comes to mole conversion exercises. Molar mass, expressed in grams per mole (g/mol), represents the weight of one mole of a substance. To calculate the molar mass of a compound, you need to know the chemical formula of the substance and the atomic mass of each element that composes it.

To illustrate this concept, let's consider the first exercise where the molar mass of chlorofluorocarbon \textbf{CF}\(_2\)\textbf{Cl}\(_2\) is determined. The process involves multiplying the atomic mass of each element by the number of atoms of that element in the formula and adding these values together. For example,

\textbf{Molar mass} = (1 x 12.01 g/mol) + (2 x 19.00 g/mol) + (2 x 35.45 g/mol)

With this calculation, we derive the molar mass of the compound, which is then used to convert a given mass of the substance into moles, providing a bridge between the mass of a substance and the number of particles contained in that mass.
Stoichiometry
Stoichiometry is the section of chemistry that deals with the calculation of the reactants and products in chemical reactions. It is grounded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products. The stoichiometric calculations often involve mole conversions, which take into account the molar mass of the substances involved.

Understanding stoichiometry is essential for solving problems like the ones given in the exercise, where you have to convert the mass of a substance to moles. Here's how the process follows:

  • Use the molar mass of the substance, derived from its chemical formula, to determine the number of moles contained in a given mass.
  • Apply this concept along with stoichiometric coefficients from a balanced chemical equation to relate amounts of one substance to another.

In the case of exercise (b), once the molar mass of iron(II) sulfate is known, the mass given in milligrams is first converted to grams, adhering to stoichiometric principles, and then to moles using the molar mass.
Chemical Formula
A chemical formula is a symbolic representation of a substance that indicates the elements present and their relative proportions. It is critical for determining the molar mass of a compound, which in turn is essential for conversions between mass and moles. The chemical formula provides the necessary information to understand the composition of a molecule and thus play a pivotal role in stoichiometry and mole conversions.

When examining a chemical formula, such as \textbf{C}\(_{15}\)\textbf{H}\(_{13}\)\textbf{ClN}\(_2\)\textbf{O} for Valium, the subscripts tell us the number of atoms of each element in one molecule of the compound. Knowing this, we can calculate its molar mass by summing the atomic masses of its constituent atoms, just as shown in the solution for exercise (c). It's fundamental to grasp the concept of a chemical formula to seamlessly transition from the symbolic to the quantitative analysis of substances in chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Riboflavin is one of the \(\mathrm{B}\) vitamins. It is also known as vitamin \(\mathrm{B}_{6}\) and is made up of carbon, hydrogen, nitrogen, and oxygen atoms. When \(10.00 \mathrm{~g}\) of vitamin \(\mathrm{B}_{6}\) is burned in oxygen, \(19.88 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(4.79 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) are obtained. Another experiment shows that vitamin \(\mathrm{B}_{6}\) is made up of \(14.89 \% \mathrm{~N}\). What is the simplest formula for vitamin \(\mathrm{B}_{6}\) ?

Calculate the molar masses (in grams per mole) of (a) cane sugar, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) (b) laughing gas, \(\mathrm{N}_{2} \mathrm{O}\). (c) vitamin A, \(\mathrm{C}_{20} \mathrm{H}_{30} \mathrm{O}\).

Ibuprofen, the active ingredient in Advil \(^{\text {m }}\), is made up of carbon, hydrogen, and oxygen atoms. When a sample of ibuprofen, weighing \(5.000 \mathrm{~g}\), burns in oxygen, \(13.86 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(3.926 \mathrm{~g}\) of water are obtaine \(\mathrm{d} .\) What is the simplest formula of ibuprofen?

Perhaps the simplest way to calculate Avogadro's number is to compare the charge on the electron, first determined by Robert Millikan in 1909, with the charge on a mole of electrons, determined electrochemically (Chapter 18). These charges, in coulombs (C), are given in Appendix 1 . Use them to calculate Avogadro's number to five significant figures.

Arrange the following in order of increasing mass. (a) a sodium ion (b) a selenium atom (c) a sulfur \(\left(\mathrm{S}_{8}\right)\) molecule (d) a scandium atom

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free