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Chapter 3: Problem 30

Calculate the mass in grams of \(13.5 \mathrm{~mol}\) of (a) vinyl chloride, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), the starting material for a plastic. (b) capsaicin, \(\mathrm{C}_{18} \mathrm{H}_{27} \mathrm{NO}_{3}\), the substance that makes red chili peppers "hot." (c) stearic acid, \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{2}\), used in soaps.

Short Answer

Expert verified
The mass in grams of 13.5 moles of: (a) Vinyl Chloride (C2H3Cl) is 843.75 g. (b) Capsaicin (C18H27NO3) is 4123.71 g. (c) Stearic Acid (C18H36O2) is 3841.29 g.

Step by step solution

01

Finding the Molar Mass of Vinyl Chloride (C2H3Cl)

To find the molar mass of Vinyl Chloride, we need to know the atomic mass of each atom in the compound. Using the periodic table, we find that: - Carbon (C) has an atomic mass of 12.01 g/mol - Hydrogen (H) has an atomic mass of 1.01 g/mol - Chlorine (Cl) has an atomic mass of 35.45 g/mol Now, we can calculate the molar mass of Vinyl Chloride: Molar mass = (2 × 12.01) + (3 × 1.01) + (1 × 35.45) = 24.02 + 3.03 + 35.45 = 62.50 g/mol
02

Mass of 13.5 mol Vinyl Chloride

Using the molar mass of Vinyl Chloride (62.50 g/mol) and the given amount of moles (13.5 mol), we can calculate the mass in grams: Mass = (13.5 mol) × (62.50 g/mol) = 843.75 g
03

Finding the Molar Mass of Capsaicin (C18H27NO3)

To find the molar mass of Capsaicin, we need to know the atomic mass of each atom in the compound. Using the periodic table, we find that: - Nitrogen (N) has an atomic mass of 14.01 g/mol - Oxygen (O) has an atomic mass of 16.00 g/mol Now, we can calculate the molar mass of Capsaicin: Molar mass = (18 × 12.01) + (27 × 1.01) + (1 × 14.01) + (3 × 16.00) = 216.18 + 27.27 + 14.01 + 48.00 = 305.46 g/mol
04

Mass of 13.5 mol Capsaicin

Using the molar mass of Capsaicin (305.46 g/mol) and the given amount of moles (13.5 mol), we can calculate the mass in grams: Mass = (13.5 mol) × (305.46 g/mol) = 4123.71 g
05

Finding the Molar Mass of Stearic Acid (C18H36O2)

To find the molar mass of Stearic Acid, we can use the atomic masses we found earlier and calculate the molar mass: Molar mass = (18 × 12.01) + (36 × 1.01) + (2 × 16.00) = 216.18 + 36.36 + 32.00 = 284.54 g/mol
06

Mass of 13.5 mol Stearic Acid

Using the molar mass of Stearic Acid (284.54 g/mol) and the given amount of moles (13.5 mol), we can calculate the mass in grams: Mass = (13.5 mol) × (284.54 g/mol) = 3841.29 g In conclusion, the mass in grams of \(13.5 \mathrm{~mol}\) of: (a) Vinyl Chloride, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), is \(843.75 \mathrm{~g}\). (b) Capsaicin, \(\mathrm{C}_{18} \mathrm{H}_{27} \mathrm{NO}_{3}\), is \(4123.71 \mathrm{~g}\). (c) Stearic Acid, \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{2}\), is \(3841.29 \mathrm{~g}\).

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Most popular questions from this chapter

Riboflavin is one of the \(\mathrm{B}\) vitamins. It is also known as vitamin \(\mathrm{B}_{6}\) and is made up of carbon, hydrogen, nitrogen, and oxygen atoms. When \(10.00 \mathrm{~g}\) of vitamin \(\mathrm{B}_{6}\) is burned in oxygen, \(19.88 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(4.79 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) are obtained. Another experiment shows that vitamin \(\mathrm{B}_{6}\) is made up of \(14.89 \% \mathrm{~N}\). What is the simplest formula for vitamin \(\mathrm{B}_{6}\) ?

Write a balanced equation for (a) the combustion (reaction with oxygen gas) of glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\), to give carbon dioxide and water. (b) the reaction between xenon tetrafluoride gas and water to give xenon, oxygen, and hydrogen fluoride gases. (c) the reaction between aluminum and iron(III) oxide to give aluminum oxide and iron. (d) the formation of ammonia gas from its elements. (e) the reaction between sodium chloride, sulfur dioxide gas, steam, and oxygen to give sodium sulfate and hydrogen chloride gas.

Balance the following equations: (a) \(\mathrm{H}_{2} \mathrm{~S}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{S}(s)+\mathrm{H}_{2} \mathrm{O}(g)\) (b) \(\mathrm{CH}_{4}(g)+\mathrm{NH}_{3}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{HCN}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (c) \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{Fe}(l)+\mathrm{H}_{2} \mathrm{O}(g)\)

Lead is a heavy metal that remains in the bloodstream, causing mental retardation in children. It is believed that \(3 \times 10^{-7} \mathrm{~g}\) of \(\mathrm{Pb}\) in \(1.00 \mathrm{~mL}\) of blood is a health hazard. For this amount of lead (a) how many atoms of lead are there in one \(\mathrm{mL}\) of a child's blood? (b) how many moles of lead are in \(1.00 \mathrm{~L}\) of blood?

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