Carbon tetrachloride, \(\mathrm{CCl}_{4}\), was a popular dry-cleaning agent until it was shown to be carcinogenic. It has a density of \(1.589 \mathrm{~g} / \mathrm{cm}^{3} .\) What volume of carbon tetrachloride will contain a total of \(6.00 \times 10^{25}\) molecules of \(\mathrm{CCl}_{4} ?\)

Short Answer

Expert verified
Answer: The volume of carbon tetrachloride containing \(6.00 \times 10^{25}\) molecules of \(\mathrm{CCl}_{4}\) is \(9,646.90 \mathrm{cm^{3}}\).

Step by step solution

01

Find the molar mass of \(\mathrm{CCl}_{4}\)

First, determine the molar mass of carbon tetrachloride. Carbon has a molar mass of \(12.01 \mathrm{~g/mol}\) and Chlorine has a molar mass of \(35.45 \mathrm{~g/mol}\). So, the molar mass of \(\mathrm{CCl}_{4}\) is: \(1(12.01 \mathrm{~g/mol}) + 4(35.45 \mathrm{~g/mol}) = 12.01 + 4(35.45) = 12.01 + 141.8 = 153.81 \mathrm{~g/mol}\)
02

Determine the number of moles of \(\mathrm{CCl}_{4}\)

Next, we need to find the number of moles of \(\mathrm{CCl}_{4}\). We can use Avogadro's number (\(6.022 \times 10^{23} \mathrm{molecules/mol})\) to find the number of moles: Number of moles = (Number of molecules given) / (Avogadro's number) Number of moles = (\(6.00 \times 10^{25} \mathrm{molecules})\) / (\(6.022 \times 10^{23} \mathrm{molecules/mol}) = 99.63 \mathrm{mol}\)
03

Calculate the mass of \(\mathrm{CCl}_{4}\)

Now we will find the mass of carbon tetrachloride containing the given molecules. This can be found using the formula: Mass = (number of moles) × (molar mass) Mass = (99.63 \mathrm{mol}) × (153.81 \mathrm{~g/mol}) = 15,335.37 \mathrm{g}$
04

Calculate the volume of \(\mathrm{CCl}_{4}\)

Finally, we will use the density formula to find the volume of carbon tetrachloride containing the given molecules: Volume = (mass) / (density) Volume = \((15,335.37 \mathrm{g})\) / \((1.589 \mathrm{g/cm^{3}})\) = 9,646.90 \mathrm{cm^{3}}$ The volume of carbon tetrachloride containing \(6.00 \times 10^{25}\) molecules of \(\mathrm{CCl}_{4}\) is \(9,646.90 \mathrm{cm^{3}}\).

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