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Chapter 4: Problem 2

The average adult has about \(16 \mathrm{~g}\) of sodium ions in her blood. Assuming a total blood volume of \(5.0 \mathrm{~L}\), what is the molarity of \(\mathrm{Na}^{+}\) ions in blood?

Short Answer

Expert verified
Answer: The molarity of sodium ions in an average adult's blood is approximately 0.14 M.

Step by step solution

01

Convert grams of sodium ions to moles

Using the periodic table, we can find the molar mass of sodium (Na), which is approximately 23 g/mol. To convert the mass of sodium ions (16 g) in the blood to moles, we can use the formula: moles = (mass) / (molar mass). moles of Na+ = \(\frac{16\mathrm{~g}}{23\frac{\mathrm{g}}{\mathrm{mol}}}\)
02

Calculate the molarity of sodium ions in blood

Molarity (M) is defined as the moles of solute per liter of solution. To find the molarity of Na+ ions in blood, we can use the formula: M = (moles of solute) / (volume of solution in L). Molarity of Na+ ions = \(\frac{\text{moles of Na}^+}{\text{volume of blood in L}}\) Now, we need to plug in the values we calculated earlier and the given blood volume: Molarity of Na+ ions = \(\frac{\frac{16\mathrm{~g}}{23\frac{\mathrm{g}}{\mathrm{mol}}}}{5.0\mathrm{~L}}\)
03

Solve for the molarity of sodium ions

Now we can solve the equation and find the molarity of Na+ ions in blood: Molarity of Na+ ions = \(\frac{\frac{16\mathrm{~g}}{23\frac{\mathrm{g}}{\mathrm{mol}}}}{5.0\mathrm{~L}} = \frac{16}{23\times5} \mathrm{mol/L} \approx 0.14 \mathrm{M}\) So, the molarity of Na+ ions in blood is approximately 0.14 M.

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Most popular questions from this chapter

III Classify each of the following half-reactions as oxidation or reduction. (a) \(\mathrm{O}_{2}(g) \longrightarrow \mathrm{O}^{2-}(a q)\) (b) \(\mathrm{MnO}_{4}^{-}(a q) \longrightarrow \mathrm{MnO}_{2}(s)\) (c) \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q) \longrightarrow \mathrm{Cr}^{3+}(a q)\) (d) \(\mathrm{Cl}^{-}(a q) \longrightarrow \mathrm{Cl}_{2}(g)\)

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