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Chapter 4: Problem 88

Use the following reactions to arrange the cations \(\mathrm{W}^{+}, \mathrm{X}^{+}, \mathrm{Y}^{+}\), and \(\mathrm{Z}^{+}\) in order of their increasing ability as oxidizing agents. $$ \begin{aligned} &\mathrm{W}^{+}+\mathrm{Z} \longrightarrow \text { no reaction } \\ &\mathrm{X}^{+}+\mathrm{W} \longrightarrow \text { no reaction } \\ &\mathrm{Y}^{+}+\mathrm{X} \longrightarrow \mathrm{X}^{+}+\mathrm{Y} \\ &\mathrm{Y}^{+}+\mathrm{Z} \longrightarrow \mathrm{Z}^{+}+\mathrm{Y} \end{aligned} $$

Short Answer

Expert verified
Question: Based on the given reactions, arrange the cations W⁺, X⁺, Y⁺, and Z⁺ in terms of their increasing ability as oxidizing agents. Answer: W⁺ < X⁺ < Z⁺ < Y⁺.

Step by step solution

01

Understand the given reactions

We are given 4 reactions involving cations W⁺, X⁺, Y⁺, and Z⁺. Two of the reactions result in no reaction, which means the cations involved cannot cause a reduction reaction in each other. The other two reactions result in a reaction, indicating that the cation can cause a reduction reaction in the other cation.
02

Analyzing no reaction cases

First, let's analyze the two reactions where no reaction occurs: 1. W⁺ + Z → no reaction: This suggests that W⁺ is not a strong enough oxidizing agent to reduce Z, and Z⁺ is not a strong enough oxidizing agent to reduce W. 2. X⁺ + W → no reaction: This suggests that X⁺ is not a strong enough oxidizing agent to reduce W, and W⁺ is not a strong enough oxidizing agent to reduce X.
03

Analyzing reactions with reactions

Now, let's analyze the two reactions where a reaction occurs: 3. Y⁺ + X → X⁺ + Y: In this reaction, Y⁺ is able to reduce X, so Y⁺ is a stronger oxidizing agent than X⁺. 4. Y⁺ + Z → Z⁺ + Y: In this reaction, Y⁺ is able to reduce Z, so Y⁺ is a stronger oxidizing agent than Z⁺.
04

Arrange the cations in order of their increasing ability as oxidizing agents

Considering the information from the reactions, we can determine the following order: 1. W⁺ is not able to reduce X or Z, so it is the weakest oxidizing agent. 2. X⁺ is reduced by Y⁺ but does not reduce W or Z, so it is weaker than Y⁺ but stronger than W⁺. 3. Z⁺ is reduced by Y⁺ and does not reduce W, so it is weaker than Y⁺ but we cannot directly compare it with X⁺ and W⁺ from the given information. 4. Y⁺ is the strongest oxidizing agent among the given cations, as it reduces both X and Z. Thus, the order of increasing ability as oxidizing agents is: W⁺ < X⁺ < Z⁺ < Y⁺.

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Most popular questions from this chapter

For each unbalanced equation given below- write unbalanced half-reactions. identify the species oxidized and the species reduced. Id identify the oxidizing and reducing agents. (a) \(\mathrm{Ag}(s)+\mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{Ag}^{+}(a q)+\mathrm{NO}(g)\) (b) \(\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{O}_{2}(g)\)

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