A tank is filled with a gas to a pressure of \(977 \mathrm{~mm} \mathrm{Hg}\) at \(25^{\circ} \mathrm{C}\). When the tank is heated, the pressure increases to \(1.50 \mathrm{~atm}\). To what temperature was the gas heated?

Short Answer

Expert verified
Answer: The final temperature of the gas when heated is approximately \(86.12^{\circ}\mathrm{C}\).

Step by step solution

01

Write down the initial conditions

The initial pressure \(P_1 = 977 \mathrm{~mm Hg}\), the initial temperature \(T_1=25^{\circ} \mathrm{C}\), and the final pressure \(P_2=1.50 \mathrm{~atm}\).
02

Convert pressures and temperatures to proper units

For consistency, let's convert pressures to atmospheres and temperatures to Kelvins. We know that \(1 \mathrm{~atm} = 760 \mathrm{~mm Hg}\) and to convert Celsius to Kelvin we just add \(273.15\). Therefore, \(P_1 = \frac{977}{760} \mathrm{~atm}\) and \(T_1 = 25 + 273.15 = 298.15\mathrm{~K}\).
03

Apply the ideal gas law in the form of \(P_1 / T_1 = P_2 / T_2\)

Now we can write the equation for the final temperature: $$\frac{P_1}{T_1} = \frac{P_2}{T_2}$$.
04

Solve for the final temperature \(T_2\)

We can rearrange the equation to solve for \(T_2\): $$T_2 = \frac{P_2 \cdot T_1}{P_1} = \frac{1.50 \mathrm{~atm} \cdot 298.15 \mathrm{~K}}{\frac{977}{760} \mathrm{~atm}}$$ Now, we can calculate the value of \(T_2\) for the final temperature: $$T_2 = \frac{1.50 \cdot 298.15}{\frac{977}{760}} \approx 359.27 \mathrm{~K}$$
05

Convert the final temperature to Celsius

Let's convert the final temperature in Kelvins to Celsius: $$T_2^{\circ}C = 359.27 \mathrm{~K} - 273.15 \approx 86.12^{\circ} \mathrm{C}$$ So, the gas was heated to a temperature of approximately \(86.12^{\circ}\mathrm{C}\).

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