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Chapter 6: Problem 53

Arrange the elements Sr, In, and Te in order of (a) decreasing atomic radius. (b) decreasing first ionization energy. (c) increasing electronegativity.

Short Answer

Expert verified
Question: Arrange the elements Sr (Strontium), In (Indium), and Te (Tellurium) in order of (a) decreasing atomic radius, (b) decreasing first ionization energy, and (c) increasing electronegativity. Answer: (a) Decreasing atomic radius: Sr > In > Te, (b) Decreasing first ionization energy: Te > In > Sr, (c) Increasing electronegativity: Sr < In < Te.

Step by step solution

01

Find the periods and groups of the elements

Consult the periodic table to find that Sr is in period 5, group 2; In is in period 5, group 13; and Te is in period 5, group 16.
02

Recall the trends for atomic radius

In the periodic table, atomic radius generally decreases as you move from left to right across a period and increases as you move down a group.
03

Arrange the elements based on atomic radius

Sr, In, and Te are all in the same period (period 5). Sr is in group 2, In is in group 13, and Te is in group 16. Since atomic radius decreases as we move across a period from left to right, the order of decreasing atomic radius is Sr > In > Te.
04

Recall the trends for ionization energy

In the periodic table, the ionization energy generally increases as you move from left to right across a period and decreases as you move down a group.
05

Arrange the elements based on first ionization energy

Since all three elements are in the same period, we only need to compare their positions within the period. Moving from left to right, the order of decreasing first ionization energy is Te > In > Sr.
06

Recall the trends for electronegativity

In the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group.
07

Arrange the elements based on electronegativity

Since all three elements are in the same period, we only need to compare their positions within the period. Moving from left to right, the order of increasing electronegativity is Sr < In < Te. Final summary: (a) Decreasing atomic radius: Sr > In > Te (b) Decreasing first ionization energy: Te > In > Sr (c) Increasing electronegativity: Sr < In < Te

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Most popular questions from this chapter

Write the symbol and the abbreviated electron configuration of the element described. (a) the metal in Group 1 whose atom is the smallest (b) the alkaline earth metal with the heaviest atom (c) the transition metal in period 4 whose atom contains the fewest protons (d) the largest metalloid atom with the maximum number of unpaired p electrons (e) an element in period 4 whose \(+2\) ion is isoelectronic with argon

Which of the following electron configurations (a-e) are for atoms in the ground state? In the excited state? Which are impossible? (a) \(1 s^{2} 2 p^{1}\) (b) \(1 s^{2} 2 s^{2} 2 p^{4}\) (c) \(1 s^{2} 2 s^{2} 2 p^{5} 3 d^{1}\) (d) \(1 s^{2} 2 s^{2} 2 p^{7} 3 s^{2}\) (e) \(1 s^{2} 2 s^{2} 2 p^{6} 4 s^{1} 3 d^{11}\)

For the following pairs of orbitals, indicate which is lower in energy in a many-electron atom. (a) \(3 \mathrm{~d}\) or \(4 \mathrm{~s}\) (b) \(4 \mathrm{f}\) or \(3 \mathrm{~d}\) (c) \(2 \mathrm{~s}\) or \(2 \mathrm{p}\) (d) \(4 \mathrm{f}\) or \(4 \mathrm{~d}\)

Consider the following transitions 1\. \(\mathrm{n}=3\) to \(\mathrm{n}=1\) 2\. \(\mathbf{n}=2\) to \(\mathbf{n}=\mathbf{3}\) 3\. \(\mathbf{n}=4\) to \(\mathbf{n}=3\) 4\. \(\mathbf{n}=3\) to \(\mathbf{n}=5\) (a) For which of the transitions is energy absorbed? (b) For which of the transitions is energy emitted? (c) Which transitions involve the ground state? (d) Which transition absorbs the most energy? (e) Which transition emits the most energy?

Which of the following electron configurations are for atoms in the ground state? In the excited state? Which are impossible? (a) \(1 s^{2} 2 s^{2} 2 p^{1}\) (b) \(1 s^{2} 1 p^{1} 2 s^{1}\) (c) \(1 s^{2} 2 s^{2} 2 p^{3} 3 s^{1}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 d^{10}\) (e) \(1 s^{2} 2 s^{2} 2 p^{5} 3 s^{1}\)
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