Several compounds have the formula \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\). Write Lewis structures for two of these compounds where the three carbon atoms are bonded to each other in a chain. The hydrogen and the oxygen atoms are bonded to the carbon atoms.

There are several isomers possible with the molecular formula C₃H₆O. We need to find two where the three carbon atoms are bonded in a chain. The two isomers that meet this criteria are propanal and propanone (also known as acetone).

Now, we need to draw the Lewis structures for propanal and propanone. For propanal: 1. Arrange the atoms in order, with the carbon atoms forming a chain: H-C-C-C-O. 2. Add in the hydrogen atoms around the carbon atoms, making sure each carbon atom forms four bonds in total. The hydrogen and the oxygen atoms will be bonded to carbon atoms. 3. Fill in the electrons around the oxygen atom to complete the octet rule. For propanone: 1. Arrange the atoms, with the carbon atoms forming a chain: H-C-C-C. 2. Place the oxygen atom between the second and third carbon atom, creating a double bond. 3. Add in the hydrogen atoms around the carbon atoms, making sure each carbon atom forms a total of four bonds. The hydrogen and the oxygen atoms will be bonded to carbon atoms. 4. Fill in the electrons around the oxygen atom to complete the octet rule. So, the Lewis structures for the two compounds are: Propanal: ``` H | H - C - C - C = O | | H H | H ``` Propanone (Acetone): ``` H | H - C - C = O - C - H | | H H | H ```