Of the four general types of solids, which one(s) (a) are generally low-boiling? (b) are ductile and malleable? (c) are generally soluble in nonpolar solvents?

Short Answer

Expert verified
Provide examples for each property. Answer: (a) Molecular solids typically exhibit low boiling points due to the weak intermolecular forces between their molecules, such as in sugar, ice, and dry ice (solid CO2). (b) Metallic solids, such as gold, silver, and copper, are ductile and malleable due to their metallic bonds and the "sea" of delocalized electrons surrounding the metal atoms. (c) Nonpolar molecular solids, like iodine (I2) and fullerenes (e.g., C60), are soluble in nonpolar solvents (e.g., hexane or benzene) because their weak London dispersion forces get disrupted by other nonpolar molecules.

Step by step solution

01

(a) Low-Boiling Solids:

Low-boiling solids are those that transition from the solid phase to the gaseous phase at relatively low temperatures. In the context of the four general types of solids, molecular solids typically exhibit low boiling points. Molecular solids consist of weak intermolecular forces (like van der Waals forces and hydrogen bonds) between their molecules, which require less energy to break. Examples of molecular solids include sugar, ice, and dry ice (solid CO2).
02

(b) Ductile and Malleable Solids:

Ductile and malleable solids are those that can be stretched or deformed without breaking or cracking. In the context of the four general types of solids, metallic solids are ductile and malleable. Metallic bonds consist of metal atoms surrounded by a "sea" of delocalized electrons that contribute to their ability to hold their structure even when significant stress is applied. Examples of ductile and malleable solids include gold, silver, and copper.
03

(c) Soluble in Nonpolar Solvents:

Solids that are soluble in nonpolar solvents generally have a similar nature as nonpolar solvents; that is, they exhibit low polarity or no polarity at all. Within the four types of solids, molecular solids (with nonpolar molecules) demonstrate solubility in nonpolar solvents. Furthermore, nonpolar molecular solids are held together by weak London dispersion forces, which get disrupted by other nonpolar molecules. Examples of nonpolar molecular solids include iodine (I2) and fullerenes (like C60), which are soluble in nonpolar solvents like hexane or benzene.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a sealed flask with a movable piston that contains \(5.25 \mathrm{~L}\) of \(\mathrm{O}_{2}\) saturated with water vapor at \(25^{\circ} \mathrm{C}\). The piston is depressed at constant temperature so that the gas is compressed to a volume of \(2.00 \mathrm{~L}\). (Use the table in Appendix 1 for the vapor pressure of water at various temperatures.) (a) What is the vapor pressure of water in the compressed gas mixture? (b) How many grams of water condense when the gas mixture is compressed?

Describe the structural units in (a) NaI (b) \(\mathrm{N}_{2}\) (c) \(\mathrm{KO}_{2}\) (d) \(\mathrm{Au}\)

A pure substance \(\mathrm{X}\) has the following properties: \(\mathrm{mp}=90^{\circ} \mathrm{C}\), increasing slightly as pressure increases; normal bp \(=120^{\circ} \mathrm{C}\); liquid vp \(=65 \mathrm{~mm} \mathrm{Hg}\) at \(100^{\circ} \mathrm{C}, 20 \mathrm{~mm} \mathrm{Hg}\) at the triple point. (a) Draw a phase diagram for X. (b) Label solid, liquid, and vapor regions of the diagram. (c) What changes occur if, at a constant pressure of \(100 \mathrm{~mm} \mathrm{Hg}\), the temperature is raised from \(100^{\circ} \mathrm{C}\) to \(150^{\circ} \mathrm{C}\) ?

Differentiate between (a) a covalent bond and a hydrogen bond. (b) normal boiling point and a boiling point. (c) the triple point and the critical point. (d) a phase diagram and a vapor pressure curve. (e) volume effect and temperature effect on vapor pressure.

It has been suggested that the pressure exerted on a skate blade is sufficient to melt the ice beneath it and form a thin film of water, which makes it easier for the blade to slide over the ice. Assume that a skater weighs \(120 \mathrm{lb}\) and the blade has an area of \(0.10 \mathrm{in}^{2} .\) Calculate the pressure exerted on the blade \(\left(1 \mathrm{~atm}=15 \mathrm{lb} / \mathrm{in}^{2}\right)\). From information in the text, calculate the decrease in melting point at this pressure. Comment on the plausibility of this explanation and suggest another mechanism by which the water film might be formed.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free