What is pressure-volume work? How is it calculated?

Short Answer

Expert verified
Pressure-volume work is the work done by or on a system during a volume change against an external pressure, calculated using the equation \( W = -P \Delta V \).

Step by step solution

01

Understanding Pressure-Volume Work

Pressure-volume work refers to the work done by or on a system when a volume change occurs against an external pressure. This concept is commonly used in thermodynamics to describe the energy transfer that occurs when a gas expands or contracts within a container.
02

Defining the Equation

The work done on or by a system during a volume change can be calculated using the equation: \( W = -P \Delta V \), where \( W \) is the work, \( P \) is the external pressure, and \( \Delta V \) is the change in volume. The negative sign indicates that work is done by the system on the surroundings if the volume increases (positive \( \Delta V \)), and work is done on the system by the surroundings if the volume decreases (negative \( \Delta V \)).
03

Calculation of Pressure-Volume Work

To determine the pressure-volume work, identify the external pressure and the initial and final volumes of the system. Calculate the change in volume, \( \Delta V \), by subtracting the initial volume from the final volume. Finally, apply these values to the equation \( W = -P \Delta V \) to compute the work.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Introduction to Thermodynamics
Thermodynamics is a branch of physics that deals with the relationships and conversions between heat and other forms of energy. In essence, it looks at how energy is transferred within systems and how this affects the physical properties of those systems. A central concept in thermodynamics is 'work', a form of energy transfer that occurs when an applied force causes a body to move.

Within the context of gases, this can be seen when a gas expands or contracts. This change can perform work on its surroundings, or the surroundings can do work on the gas. This interaction is described by the principles of thermodynamics and is quantified as pressure-volume work. Understanding the laws of thermodynamics, such as the conservation of energy, is essential for calculating and predicting how systems will behave when they interact with their environment.
Energy Transfer in Gases
When discussing gases, the energy transfer often involves changes in volume and pressure. This is particularly evident in pressure-volume work. Imagine a gas that is contained in a cylinder with a movable piston; when the gas expands, it pushes against the piston, transferring energy to it. Conversely, if the piston compresses the gas, energy is transferred from the piston to the gas.

This type of energy transfer is crucial in many practical applications, such as internal combustion engines and HVAC systems. By understanding how gases transfer energy through expansion and compression, we can better design systems that efficiently utilize this energy transfer, whether it's to power a vehicle or to regulate temperature in buildings.
Work Calculation in Physics
Work calculation in physics is a means to quantify the energy transferred when a force causes a displacement. In the context of pressure-volume work, the force is due to the pressure exerted by the gas, and the displacement is the change in volume of the gas. As per the equation \( W = -P \Delta V \), 'work' (W) is the product of pressure (P) and the volume change (\( \Delta V \)).

The negative sign in the equation is crucial; it signifies that when a gas expands (positive \( \Delta V \)), work is done by the gas on its environment. Conversely, when a gas is compressed (negative \( \Delta V \)), work is done on the gas by its surroundings. Calculating work in this manner allows scientists and engineers to understand and leverage the mechanical energy transfers occurring due to volume changes in gases, which is foundational in various technological and industrial processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Is each process exothermic or endothermic? Indicate the sign of \(\Delta H .\) a. natural gas burning on a stove b. isopropyl alcohol evaporating from skin c. water condensing from steam

Instant cold packs used to ice athletic injuries on the field contain ammonium nitrate and water separated by a thin plastic divider. When the divider is broken, the ammonium nitrate dissolves according to the endothermic reaction: $$\mathrm { NH } _ { 4 } \mathrm { NO } _ { 3 } ( s ) \longrightarrow \mathrm { NH } _ { 4 } ^ { + } ( a q ) + \mathrm { NO } _ { 3 } ^ { - } ( a q )$$ In order to measure the enthalpy change for this reaction, 1.25 g of \(\mathrm { NH } _ { 4 } \mathrm { NO } _ { 3 }\) is dissolved in enough water to make 25.0\(\mathrm { mL }\) of solution. The initial temperature is \(25.8 ^ { \circ } \mathrm { C }\) , and the final temperature (after the solid dissolves) is \(21.9 ^ { \circ } \mathrm { C }\) . Calculate the change in enthalpy for the re- action in kJ. (Use 1.0\(\mathrm { g } / \mathrm { mL }\) as the density of the solution and 4.18\(\mathrm { J } / \mathrm { g } \cdot ^ { \circ } \mathrm { C }\) as the specific heat capacity.)

During an energy exchange, a chemical system absorbs energy from its surroundings. What is the sign of \(\Delta E _ { \text { wh } }\) for this process? Explain.

From a molecular viewpoint, where does the energy emitted in an exothermic chemical reaction come from? Why does the reaction mixture undergo an increase in temperature even though energy is emitted?

Which statement is true of a reaction in which \(\Delta V\) is positive? Explain. a. \(\Delta H=\Delta E\) b. \(\Delta H>\Delta E\) c. \(\Delta H<\Delta E\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free