Which combinations of \(n\) and \(l\) represent real orbitals, and which do not exist? $$\begin{array}{lllll}{\text { a. } 1 s} & {\text { b. } 2 p} & {\text { c. } 4 s} & {\text { d. } 2 d}\end{array}$$

Short Answer

Expert verified
Real orbitals are 1s, 2p, and 4s. The 2d orbital does not exist because the value of l is too high for the given value of n.

Step by step solution

01

Understand Quantum Numbers

The principal quantum number (n) specifies the energy level of an electron in an atom and can be any positive integer. The azimuthal quantum number (l) determines the shape of an orbital and can be any integer from 0 to n-1.
02

Verify Orbital n=1, l=0 (1s)

For a 1s orbital, n=1. The permissible values of l range from 0 to n-1, so for n=1 the only value l can take is 0. Since l=0 corresponds to an s orbital, 1s is a real orbital.
03

Verify Orbital n=2, l=1 (2p)

For a 2p orbital, n=2. The permissible values of l for n=2 are 0 and 1. Since l=1 corresponds to a p orbital, 2p is a real orbital.
04

Verify Orbital n=4, l=0 (4s)

For a 4s orbital, n=4. The permissible values of l range from 0 to 3. Since l=0 corresponds to an s orbital, 4s is a real orbital.
05

Verify Orbital n=2, l=2 (2d)

For a 2d orbital, n=2. The permissible values of l for n=2 are 0 and 1 only. l=2 is not possible for n=2 as l must be less than n. Thus, a 2d orbital does not exist.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, often denoted by the symbol n, is integral to understanding the arrangement and energy of electrons in an atom. It defines the energy levels or shells in which electrons reside with values that can be any positive integer (1, 2, 3, ...).

As n increases, the energy level and the radius of the electron's orbit do as well, which means electrons are located further from the nucleus. In the context of the exercise, for instance, n=1 corresponds to the innermost shell where the lowest energy electrons are found, while n=4 indicates a much higher energy level with electrons further away from the nucleus. This quantum number is crucial in determining the overall structure and stability of electronic configurations within atoms.
Azimuthal Quantum Number
The azimuthal quantum number, labeled as l, is responsible for defining the shape of the electron orbitals within a given principal energy level. It can range from 0 to n-1, where n is the principal quantum number. Each value of l corresponds to a specific type of orbital:
  • ( l=0 ) s-orbitals
  • ( l=1 ) p-orbitals
  • ( l=2 ) d-orbitals
  • ( l=3 ) f-orbitals

The exercise demonstrates how the combination of n and l determines the existence of specific orbitals. For example, when n=2, the possible values of l are 0 and 1 (s and p orbitals), making it clear why a 2d (n=2, l=2) orbital cannot exist.
Electron Orbitals
Electron orbitals are regions around the nucleus of an atom where electrons are most likely to be found. Each orbital can hold a maximum of two electrons. The principal and azimuthal quantum numbers together define these orbitals. The n value indicates the energy level, while l specifies the orbital's shape within that level.

Using the knowledge of quantum numbers, we can denote orbitals with notations like 1s, 2p, or 4s, as seen in the exercise. These notations show directly which energy level and type of orbital an electron occupies. For example, the 1s orbital is the lowest energy state where electrons are very close to the nucleus and housed within a spherical shape.
Orbital Shapes
The shape of an orbital is directly correlated with the azimuthal quantum number (l). Understanding these shapes is essential when visualizing how electrons inhabit specific regions around the nucleus.

For s-orbitals (l=0), the shape is spherical, encompassing the nucleus uniformly in all directions. When we move to p-orbitals (l=1), the shape becomes dumbbell or figure-eight shaped, with three possible orientations in three-dimensional space (px, py, and pz). Similarly, d orbitals feature more complex shapes and are found when l=2, showing even more varied spatial distributions. The orbital shapes play a pivotal role in determining atomic bonding and electron density distribution in molecules.

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Most popular questions from this chapter

Which set of quantum numbers cannot occur together to specify an orbital? $$\begin{array}{l}{\text { a. } n=2, l=1, m_{l}=-1} \\ {\text { b. } n=3, l=2, m_{l}=0} \\ {\text { c. } n=3, l=3, m_{l}=2} \\ {\text { d. } n=4, l=3, m_{l}=0}\end{array}$$

The resolution limit of a microscope is roughly equal to the wavelength of light used in producing the image. Electron microscopes use an electron beam (in place of photons) to produce much higher resolution images, about 0.20 \(\mathrm{nm}\) in modern instruments. Assuming that the resolution of an electron microscope is equal to the de Broglie wavelength of the electrons used, to what speed must the electrons be accelerated to obtain a resolution of 0.20 \(\mathrm{nm} ?\)

An electron in a hydrogen atom is excited with electrical energy to an excited state with \(n=2 .\) The atom then emits a photon. What is the value of \(n\) for the electron following the emission?

The human eye contains a molecule called 11-\(cis\)-retinal that changes shape when struck with light of sufficient energy. The change in shape triggers a series of events that results in an electrical signal being sent to the brain. The minimum energy required to change the conformation of 11-\( cis \)-retinal within the eye is about 164 kJ/mol. Calculate the longest wavelength visible to the human eye.

Suppose that in an alternate universe, the possible values of \(l\) are the integer values from 0 to \(n(\) instead of 0 to \(n-1) .\) Assuming no other differences between this imaginary universe and ours, how many orbitals would exist in each level? $$\begin{array}{ll}{\text { a. }} & {n=1} \\ {\text { b. }} & {n=2} \\\ {\text { c. }} & {n=3}\end{array}$$

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