Chapter 5: Problem 5
What is the difference between an empirical formula and a molecular formula?
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 5: Problem 5
What is the difference between an empirical formula and a molecular formula?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeWithout doing any calculations, arrange the elements in \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in order of decreasing mass percent composition.
Determine the number of moles of hydrogen atoms in each sample. $$ \begin{array}{l}{\text { a. } 0.0885 \text { mol } \mathrm{C}_{4} \mathrm{H}_{10}} \\ {\text { b. } 1.3 \mathrm{mol} \mathrm{CH}_{4}} \\\ {\text { c. } 2.4 \mathrm{mol} \mathrm{C}_{6} \mathrm{H}_{12}} \\ {\text { d. } 1.87 \mathrm{mol} \mathrm{C}_{8} \mathrm{H}_{18}}\end{array} $$
Estrone, which contains only carbon, hydrogen, and oxygen, is a female sexual hormone that occurs in the urine of pregnant women. Combustion analysis of a 1.893 -g sample of estrone produces 5.545 \(\mathrm{g}\) of \(\mathrm{CO}_{2}\) and 1.388 \(\mathrm{g} \mathrm{H}_{2} \mathrm{O}\) . The molar mass of estrone is 270.36 \(\mathrm{g} / \mathrm{mol}\) . Find its molecular formula.
Estradiol is a female sexual hormone that causes maturation and maintenance of the female reproductive system. Elemental analysis of estradiol gives the following mass percent composition: \(\mathrm{C} 79.37 \%, \mathrm{H}\) \(8.88 \%, \mathrm{O} 11.75 \% .\) The molar mass of estradiol is 272.37 \(\mathrm{g} / \mathrm{mol} .\) Find the molecular formula of estradiol.
Formula Mass and the Mole Concept for Compounds Calculate the number of moles in each sample. $$ \begin{array}{llll}{\text { a. } 72.5 \mathrm{gCCl}_{4}} & {\text { b. } 12.4 \mathrm{g} \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}} \\ {\text { c. } 25.2 \mathrm{kg} \mathrm{C}_{2} \mathrm{H}_{2}} & {\text { d. } 12.3 \mathrm{g} \text { of dinitrogen monoxid }}\end{array} $$
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