Chapter 8: Problem 12
What is a combustion reaction? Why are they important? Give an example.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 8: Problem 12
What is a combustion reaction? Why are they important? Give an example.
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeWrite a balanced chemical equation for each reaction. a. Solid lead(II) sulfide reacts with aqueous hydrobromic acid (HBr) to form solid lead(II) bromide and dihydrogen monosulfide gas. b. Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane \(\left(\mathrm{CH}_{4}\right)\) and liquid water. c. Aqueous hydrochloric acid (HCl) reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. d. Liquid pentane \(\left(\mathrm{C}_{5} \mathrm{H}_{12}\right)\) reacts with gaseous oxygen to form gaseous carbon dioxide and liquid water.
Write a balanced chemical equation for each reaction. a. Solid copper reacts with solid sulfur to form solid copper(I) sulfide. b. Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water. c. Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. d. Gaseous ammonia (NH \(_{3} )\) reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water.
The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane \(\left(\mathrm{C}_{8} \mathrm{H}_{18}\right)\) and calculate the mass ( in \(\mathrm{kg}\) ) of carbon dioxide that is added to the atmosphere per 1.0 \(\mathrm{kg}\) of octane burned. (Hint: Begin by writing a balanced equation for the com- bustion reaction.
In a popular classroom demonstration, solid sodium is added to liquid water and reacts to produce hydrogen gas and aqueous sodium hydroxide. Write a balanced chemical equation for this reaction.
Consider the reaction: $$4 \mathrm{K}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{K}_{2} \mathrm{O}(s)$$ The molar mass of \(\mathrm{K}\) is 39.09 \(\mathrm{g} / \mathrm{mol}\) and that of \(\mathrm{O}_{2}\) is 32.00 \(\mathrm{g} / \mathrm{mol}\) . Without doing any calculations, choose the conditions under which potassium is the limiting reactant and explain your reasoning. \begin{equation} \begin{array}{ll}{\text { a. } 170 \mathrm{gK}, 31 \mathrm{gO}_{2}} & {\text { b. } 16 \mathrm{gK}, 2.5 \mathrm{gO}_{2}} \\ {\text { c. } 165 \mathrm{kg} \mathrm{K}, 28 \mathrm{kg} \mathrm{O}_{2}} & {\text { d. } 1.5 \mathrm{g} \mathrm{K}, 0.38 \mathrm{g} \mathrm{O}_{2}}\end{array} \end{equation}
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