Chapter 1: Problem 51
The mass ratio of sodium to fluorine in sodium fluoride is 1.21:1. A sample of sodium fluoride produces 28.8 g of sodium upon decomposition. How much fluorine (in grams) is formed?
Short Answer
Expert verified
The sample of sodium fluoride will produce approximately 23.8 grams of fluorine upon decomposition.
Step by step solution
01
Interpret the Mass Ratio
The problem gives us the mass ratio of sodium to fluorine in sodium fluoride as 1.21:1. This means that for every 1.21 grams of sodium, there is 1 gram of fluorine.
02
Find the Total Mass of Fluorine
Since 28.8 grams of sodium are produced, we need to find out how many grams of fluorine correspond to this amount of sodium. The mass of fluorine is calculated by dividing the mass of sodium by the mass ratio of sodium to fluorine. Therefore, the fluorine mass is calculated as follows: calculated fluorine mass = \( \frac{28.8 \text{ g of Na}}{1.21} \)
03
Calculate the Mass of Fluorine
Perform the division to determine the mass of fluorine: \[ \text{calculated fluorine mass} = \frac{28.8}{1.21} \approx 23.8 \text{ grams} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Ratio
The mass ratio in chemistry is an essential concept, especially when it comes to understanding chemical combinations. It is the ratio of the masses of one element to another element when combined in a compound. For instance, the mass ratio of sodium to fluorine in sodium fluoride tells us how much of each element is present in a sample of the compound. This ratio can be used to predict the masses of reactants or products in a chemical reaction.
When the mass ratio of sodium to fluorine is given as 1.21:1, it indicates that for every 1.21 grams of sodium, there's precisely 1 gram of fluorine. Understanding this ratio allows us to calculate the mass of one substance when given a mass of the other substance, by using a simple proportion. In practical problems, knowing the mass ratio aids in determining how much of a reactant is necessary or how much of a product is created during a reaction.
When the mass ratio of sodium to fluorine is given as 1.21:1, it indicates that for every 1.21 grams of sodium, there's precisely 1 gram of fluorine. Understanding this ratio allows us to calculate the mass of one substance when given a mass of the other substance, by using a simple proportion. In practical problems, knowing the mass ratio aids in determining how much of a reactant is necessary or how much of a product is created during a reaction.
Chemical Decomposition
Chemical decomposition is a type of chemical reaction where a single compound breaks down into two or more simpler substances. It represents a key reaction type in both academic studies and various industrial processes. The decomposition of sodium fluoride, for example, produces elemental sodium and fluorine.
During decomposition, the bonds within the compound are broken, requiring an input of energy. This can be achieved through various means such as heating, the application of an electric current, or exposure to light. The practical implication of understanding chemical decomposition is significant; it entails being able to predict the amounts and identities of substances produced when a compound decomposes. In educational contexts, this concept is crucial for solving stoichiometry problems involving decomposition reactions.
During decomposition, the bonds within the compound are broken, requiring an input of energy. This can be achieved through various means such as heating, the application of an electric current, or exposure to light. The practical implication of understanding chemical decomposition is significant; it entails being able to predict the amounts and identities of substances produced when a compound decomposes. In educational contexts, this concept is crucial for solving stoichiometry problems involving decomposition reactions.
Stoichiometric Calculation
Stoichiometric calculations are the cornerstone of analytical chemistry. These calculations enable chemists to use balanced chemical equations to determine the exact amounts of reactants and products involved in a chemical reaction. A balanced equation follows the law of conservation of mass, which states that mass is neither created nor destroyed in a chemical reaction.
The process involves using the mole concept, molar mass, and Avogadro's number to convert between mass, moles, and particle count. For example, when computing the amount of fluorine formed from the decomposition of sodium fluoride, the mass ratio is used alongside the given mass of sodium to find the corresponding mass of fluorine. It's a mathematical translation of chemical relationships, serving as the basis for predicting reaction outcomes and designing chemical processes.
The process involves using the mole concept, molar mass, and Avogadro's number to convert between mass, moles, and particle count. For example, when computing the amount of fluorine formed from the decomposition of sodium fluoride, the mass ratio is used alongside the given mass of sodium to find the corresponding mass of fluorine. It's a mathematical translation of chemical relationships, serving as the basis for predicting reaction outcomes and designing chemical processes.
Mole Concept
The mole concept is a fundamental principle in stoichiometry, which provides a way to measure the amount of substance. A mole is defined as the amount of substance that contains as many entities (atoms, molecules, ions, or other particles) as there are atoms in 12 grams of carbon-12. One mole corresponds to Avogadro's number, approximately 6.022 x 10^23 entities.
The mole concept allows chemists to count atoms and molecules in a macroscopic sample by weighing it. For instance, having the mass of sodium can be translated into moles of sodium, which can then be related to moles of fluorine using the correct stoichiometry from the balanced equation. This concept is vital for stoichiometric calculations, as it establishes a direct link between mass and number of particles, enabling precise quantitative analysis and conversion in chemical equations.
The mole concept allows chemists to count atoms and molecules in a macroscopic sample by weighing it. For instance, having the mass of sodium can be translated into moles of sodium, which can then be related to moles of fluorine using the correct stoichiometry from the balanced equation. This concept is vital for stoichiometric calculations, as it establishes a direct link between mass and number of particles, enabling precise quantitative analysis and conversion in chemical equations.