Chapter 14: Problem 58
The half-life for the radioactive decay of C-14 is 5730 years and is independent of the initial concentration. How long does it take for 25% of the C-14 atoms in a sample of C-14 to decay? If a sample of C-14 initially contains 1.5 mmol of C-14, how many millimoles are left after 2255 years?
Short Answer
Expert verified
It takes 5730 years for 25% of the C-14 atoms to decay. After 2255 years, about 1.1814 mmol of the initial 1.5 mmol of C-14 remains.
Step by step solution
01
Understand the Concept of Half-life
The half-life is the amount of time it takes for half of the radioactive isotope to decay. Since the half-life of C-14 is 5730 years, in this period, the quantity of C-14 will reduce to half of its initial amount regardless of the starting concentration.
02
Calculate the Fraction Remaining After One Half-life
After one half-life (5730 years), 50% of the C-14 would remain. To find out how long it takes for 25% to decay, we recognize that this would leave 75% of the original amount.
03
Determine Time for 25% Decay
75% remaining corresponds to the halfway point between 100% (initial quantity) and 50% (quantity after one half-life). Thus, it takes one half-life (5730 years) to go from 100% to 50%, and it will take another half-life to go from 50% to 25%. So, the time taken for 25% of C-14 to decay is one full half-life, which is 5730 years.
04
Calculate the Amount of C-14 Left After 2255 Years Using the Decay Formula
The decay can be described by the formula \( N = N_0 \left(\frac{1}{2}\right)^{\frac{t}{T}} \), where \( N \) is the remaining quantity of C-14, \( N_0 \) is the initial quantity, \( t \) is the time elapsed, and \( T \) is the half-life. We are given \( N_0 = 1.5 \) mmol and \( t = 2255 \) years. Insert the values and solve for \( N \).
05
Insert Values and Solve
Plugging in the values into the decay formula, we get \( N = 1.5 \times \left(\frac{1}{2}\right)^{\frac{2255}{5730}} \).
06
Calculate the Fraction
Calculate the exponent \( \frac{2255}{5730} \approx 0.3937 \), then raise \(\frac{1}{2}\) to that power to find the fraction remaining after 2255 years.
07
Determine the Amount Remaining
After calculation, the remaining fraction is \( 0.5^{0.3937} \approx 0.7876 \). Then multiply the initial quantity 1.5 mmol by 0.7876 to determine the amount remaining after 2255 years.
08
Find the Final Amount in mmol
The final remaining amount of C-14 is \( 1.5 \times 0.7876 \approx 1.1814 \) mmol.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life Calculation
Understanding the half-life of a radioactive isotope like Carbon-14 (C-14) is crucial in determining how its concentration changes over time. The half-life is the time required for exactly half of the entities to decay, reducing the original quantity to 50%. It's a constant figure for each radioactive isotope and for C-14, it stands at 5730 years.
For example, if we start with a 100% concentration of C-14, after one half-life (5730 years), only 50% remains. This concept allows us to predict how much of a substance will remain after any given period. If you were asked how long it would take for 25% of a C-14 sample to decay, which means you're left with 75% of the original, you could use this concept to deduce that it would take exactly one half-life. That's because going from 100% to 50% takes one half-life, and as radioactive decay is a logarithmic process, the next 50% to decay (leaving 25% of the original) also takes one half-life.
For example, if we start with a 100% concentration of C-14, after one half-life (5730 years), only 50% remains. This concept allows us to predict how much of a substance will remain after any given period. If you were asked how long it would take for 25% of a C-14 sample to decay, which means you're left with 75% of the original, you could use this concept to deduce that it would take exactly one half-life. That's because going from 100% to 50% takes one half-life, and as radioactive decay is a logarithmic process, the next 50% to decay (leaving 25% of the original) also takes one half-life.
Radioactive Decay Formula
To express the decay of radioactive isotopes mathematically, we use the radioactive decay formula: \[ N = N_0 \left(\frac{1}{2}\right)^{\frac{t}{T}} \]Where:
- \( N \) represents the remaining quantity of the isotope after time \( t \).
- \( N_0 \) is the initial quantity of the isotope.
- \( t \) is the time elapsed.
- \( T \) is the half-life of the isotope.
Carbon-14 Dating
Carbon-14 dating, also known as radiocarbon dating, is a method used to determine the age of an object containing organic material by measuring the levels of C-14 it contains. Because living organisms continuously exchange carbon with their environment, including a fixed ratio of C-14, the proportion of C-14 in a sample reflects the time elapsed since the organism ceased exchanging carbon (usually its death).
For instance, archaeologists implement carbon-14 dating to determine the age of ancient artifacts or fossils. By measuring how much C-14 has decayed in the sample and using the known half-life of C-14, scientists can calculate how many half-lives have passed since the death of the organism. This leads to an age estimate for the sample. The half-life is the cornerstone in these calculations, making the understanding of its calculation, along with the decay formula, essential for accurate carbon dating.
For instance, archaeologists implement carbon-14 dating to determine the age of ancient artifacts or fossils. By measuring how much C-14 has decayed in the sample and using the known half-life of C-14, scientists can calculate how many half-lives have passed since the death of the organism. This leads to an age estimate for the sample. The half-life is the cornerstone in these calculations, making the understanding of its calculation, along with the decay formula, essential for accurate carbon dating.