Chapter 16: Problem 104
Determine if each salt will form a solution that is acidic, basic, or pH-neutral. a. Al(NO3)3 b. C2H5NH3NO3 c. K2CO3 d. RbI e. NH4ClO
Short Answer
Expert verified
a. Acidic, b. Acidic, c. Basic, d. pH-neutral, e. Acidic
Step by step solution
01
Analyze Al(NO3)3
Al(NO3)3 is formed by the reaction between a weak base, Al(OH)3, and a strong acid, HNO3. The anion NO3- is the conjugate base of the strong acid and does not affect the pH significantly. However, Al3+, being the conjugate acid of a weak base, will hydrolyze water to form H+ ions, making the solution acidic.
02
Analyze C2H5NH3NO3
C2H5NH3NO3 consists of C2H5NH3+ cation, which is the conjugate acid of a weak base (C2H5NH2), and the anion NO3-. Since NO3- is not basic and the C2H5NH3+ can donate H+ ions to the water, the solution will be acidic.
03
Analyze K2CO3
K2CO3 is a salt from strong base KOH and weak acid, H2CO3. The CO3^2- anion will react with water to form OH- ions, therefore the solution will be basic.
04
Analyze RbI
RbI is composed of Rb+, which is the cation of a strong base RbOH, and I-, which is the anion of the strong acid HI. Neither ion hydrolyzes significantly so the salt will form a pH-neutral solution.
05
Analyze NH4ClO
NH4ClO is a salt derived from the weak acid HClO and NH4+, which is the conjugate acid of a weak base NH3. NH4+ will hydrolyze and form H+ ions whereas ClO- does not hydrolyze significantly. This means the solution will be acidic.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Acidic and Basic Salts
Understanding the nature of salt solutions begins by recognizing that salts can cause the resulting solution to be acidic, basic, or neutral. Acidic salts are those which come from the neutralization of a strong acid and a weak base. For instance, in step 1 and step 2 of the exercise, Al(NO3)3 and C2H5NH3NO3 are examples of acidic salts. The reason lies in the fact that their cations (Al3+ and C2H5NH3+, respectively) are capable of reacting with water, a process known as hydrolysis, to release H+ ions into the solution. This increases the concentration of H+ ions, lowering the pH and hence creating an acidic medium.
Conversely, basic salts result from the neutralization of a strong base and a weak acid. Take K2CO3 from step 3 for example. The carbonate ion (CO3^2-) is the result of neutralizing H2CO3 with a strong base. This ion will hydrolyze to produce OH- ions, which elevate the OH- concentration and raise the pH, thereby making the solution basic. It's critical to recognize these ions' behavior in water to predict the pH of their solutions effectively.
Conversely, basic salts result from the neutralization of a strong base and a weak acid. Take K2CO3 from step 3 for example. The carbonate ion (CO3^2-) is the result of neutralizing H2CO3 with a strong base. This ion will hydrolyze to produce OH- ions, which elevate the OH- concentration and raise the pH, thereby making the solution basic. It's critical to recognize these ions' behavior in water to predict the pH of their solutions effectively.
Hydrolysis of Salts
Hydrolysis of salts refers to the reaction of salt ions with water to form an acidic or basic solution. This pivotal concept helps us decipher why certain solutions exhibit certain pH values. Hydrolysis occurs when an ion reacts with water, accepting or donating a hydrogen ion (H+).
As detailed in the exercise's solutions, for Al(NO3)3 in step 1, the Al3+ ion reacts with water, which results in the production of H+ ions. The NO3- ion, however, does not react with water since it is the conjugate base of a strong acid and is, therefore, considered aweak base incapable of significantly changing the pH of the solution. Meanwhile, for NH4ClO in step 5, the NH4+ ion is a weak acid and also hydrolyzes to release H+ ions, while ClO- remains relatively inactive in terms of hydrolysis. The tendency of a salt ion to hydrolyze is linked to the strengths of its parent acid or base—a weak acid or base would produce ions more likely to undergo hydrolysis.
As detailed in the exercise's solutions, for Al(NO3)3 in step 1, the Al3+ ion reacts with water, which results in the production of H+ ions. The NO3- ion, however, does not react with water since it is the conjugate base of a strong acid and is, therefore, considered aweak base incapable of significantly changing the pH of the solution. Meanwhile, for NH4ClO in step 5, the NH4+ ion is a weak acid and also hydrolyzes to release H+ ions, while ClO- remains relatively inactive in terms of hydrolysis. The tendency of a salt ion to hydrolyze is linked to the strengths of its parent acid or base—a weak acid or base would produce ions more likely to undergo hydrolysis.
Conjugate Acid-Base Pairs
The concept of conjugate acid-base pairs is central to understanding the pH of salt solutions. Each pair consists of two species that transform into each other by the gain or loss of a proton (H+ ion). When an acid donates an H+ ion, it becomes its conjugate base, while a base accepting an H+ ion becomes its conjugate acid.
In the context of the given exercise, the cation C2H5NH3+ in step 2 is the conjugate acid of a weak base (ethanamine), indicating that it can give up an H+ ion to the solution. Similarly, the CO3^2- anion in K2CO3 (step 3) is the conjugate base of a weak acid (carbonic acid), thus capable of attracting an H+ ion to form OH- ions making the solution basic. Since none of the ions from RbI (step 4) tend to gain or lose H+ ions readily, they don't form a conjugate acid-base pair that significantly affects the pH, rendering the solution pH-neutral. Recognizing these pairs and their relative strengths is crucial in predicting the behavior of salts in solution.
In the context of the given exercise, the cation C2H5NH3+ in step 2 is the conjugate acid of a weak base (ethanamine), indicating that it can give up an H+ ion to the solution. Similarly, the CO3^2- anion in K2CO3 (step 3) is the conjugate base of a weak acid (carbonic acid), thus capable of attracting an H+ ion to form OH- ions making the solution basic. Since none of the ions from RbI (step 4) tend to gain or lose H+ ions readily, they don't form a conjugate acid-base pair that significantly affects the pH, rendering the solution pH-neutral. Recognizing these pairs and their relative strengths is crucial in predicting the behavior of salts in solution.