Chapter 8: Problem 29
If 123 mL of a 1.1 M glucose solution is diluted to 500.0 mL, what is the molarity of the diluted solution?
Short Answer
Expert verified
The molarity of the diluted solution is approximately 0.27 M.
Step by step solution
01
Understand the Concept of Dilution
Dilution is the process of reducing the concentration of a solute in a solution, usually by adding more solvent. The amount of solute stays the same, meaning the moles of solute before and after the dilution remain constant. We can express this with the formula: M1 * V1 = M2 * V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
02
Identify Known Quantities
We're given the initial molarity (M1) of 1.1 M, the initial volume (V1) of 123 mL, and the final volume (V2) of 500.0 mL. Our goal is to find the final molarity (M2).
03
Convert Milliliters to Liters
Since molarity is expressed in moles per liter, we need to convert the volume from milliliters to liters. So, V1 = 123 mL * (1 L / 1000 mL) = 0.123 L and V2 = 500.0 mL * (1 L / 1000 mL) = 0.500 L.
04
Plug the Values into the Dilution Formula
Using the dilution formula (M1 * V1 = M2 * V2), we can now plug in the known values to find M2: (1.1 M) * (0.123 L) = M2 * (0.500 L).
05
Solve for the Final Molarity M2
To isolate M2, we divide both sides of the equation by the final volume (V2). Thus, M2 = (1.1 M * 0.123 L) / 0.500 L.
06
Calculate the Result
M2 = (1.1 * 0.123) / 0.500 = 0.1353 / 0.500 = 0.2706 M. This is the molarity of the diluted solution.
07
Round to Appropriate Significant Figures
The given volumes have 3 and 4 significant figures, respectively, and the initial molarity has 2 significant figures. We should round the final answer to 2 significant figures since the least number of significant figures is 2 in 1.1M. Therefore, the molarity of the diluted solution is 0.27 M.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molarity
When studying solutions in chemistry, understanding molarity is essential. Molarity, symbolized by the capital letter 'M', stands for the concentration of a solute in a solution. It is a measure of the number of moles of solute per liter of solution. The mole is the standard unit for the amount of substance in the International System of Units (SI), and it helps chemists quantify how much of a substance they have.
Calculating molarity involves using the formula:
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \]
To understand this better, let's consider a real-world example. If you stir a spoonful of sugar into a glass of water, you create a sugar solution. The molarity of this solution depends on the number of moles of sugar (the solute) and the volume of water (the solvent) in the glass. Generally, scientists use molarity because it allows for a standardized way to express concentrations, which is useful for preparing solutions, conducting experiments, and stoichiometric calculations.
Calculating molarity involves using the formula:
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \]
To understand this better, let's consider a real-world example. If you stir a spoonful of sugar into a glass of water, you create a sugar solution. The molarity of this solution depends on the number of moles of sugar (the solute) and the volume of water (the solvent) in the glass. Generally, scientists use molarity because it allows for a standardized way to express concentrations, which is useful for preparing solutions, conducting experiments, and stoichiometric calculations.
Dilution Formula
Dilution is a crucial process in chemistry for adjusting the concentration of a solution. It involves adding more solvent to the solution without altering the amount of solute. To calculate the new concentration after dilution, the dilution formula is used:
\[ M1 \times V1 = M2 \times V2 \]
This formula states that the product of the initial molarity (M1) and the initial volume (V1) equals the product of the final molarity (M2) and the final volume (V2).
Why is this equation so practical? It allows you to calculate any one of the variables as long as the other three are known, and it's based on the conservation of the number of moles of the solute. Whether you are a scientist preparing a specific concentration for a reaction or a student in a lab exercise, understanding and applying the dilution formula is a fundamental skill in chemistry. It ensures accurateness when preparing solutions of desired molar concentrations.
\[ M1 \times V1 = M2 \times V2 \]
This formula states that the product of the initial molarity (M1) and the initial volume (V1) equals the product of the final molarity (M2) and the final volume (V2).
Why is this equation so practical? It allows you to calculate any one of the variables as long as the other three are known, and it's based on the conservation of the number of moles of the solute. Whether you are a scientist preparing a specific concentration for a reaction or a student in a lab exercise, understanding and applying the dilution formula is a fundamental skill in chemistry. It ensures accurateness when preparing solutions of desired molar concentrations.
Significant Figures
Significant figures in measurements convey the precision of the recorded data. When performing calculations, it's important to consider the number of significant figures because this affects the accuracy of your final answer. The rules for significant figures are used to determine which digits in a number are meaningful and contribute to its precision.
Important Rules for Significant Figures:
- Zeros between non-zero digits are always significant.
- Leading zeros are not significant as they only indicate the position of the decimal point.
- Trailing zeros in a number are significant if the number contains a decimal point.
Volume Conversion
Volume conversion is a fundamental aspect of solving chemistry problems, especially when dealing with solutions. Since molarity is expressed in terms of volume in liters, converting volumes from one unit to another (e.g., milliliters to liters) may be necessary to proceed with calculations. The conversion between milliliters (mL) and liters (L) is straightforward because it's based on the SI unit system where 1,000 milliliters is equal to 1 liter.
To convert milliliters to liters, the formula is:
\[ L = \frac{mL}{1000} \]
And to convert liters to milliliters:
\[ mL = L \times 1000 \]
Remembering these conversions helps prevent mistakes in calculations and ensures that all volume units align correctly. This is particularly important in lab settings where precision can greatly affect the outcome of experiments and in instances like medication dosing where the consequences of errors could be significant.
To convert milliliters to liters, the formula is:
\[ L = \frac{mL}{1000} \]
And to convert liters to milliliters:
\[ mL = L \times 1000 \]
Remembering these conversions helps prevent mistakes in calculations and ensures that all volume units align correctly. This is particularly important in lab settings where precision can greatly affect the outcome of experiments and in instances like medication dosing where the consequences of errors could be significant.