Use appropriate metric prefixes to write the following measurements without use of exponents: (a) \(2.3 \times 10^{-10} \mathrm{~L}\) (b) \(4.7 \times 10^{-6} \mathrm{~g}\), (c) \(1.85 \times 10^{-12} \mathrm{~m}\) (d) \(16.7 \times 10^{6} \mathrm{~s}\); (e) \(15.7 \times 10^{3} \mathrm{~g}\) (f) \(1.34 \times 10^{-3} \mathrm{~m},(\mathrm{~g}) 1.84 \times 10^{2} \mathrm{~cm}\)

Short Answer

Expert verified
(a) 230 pL (b) 4.7 µg (c) 1.85 pm (d) 16.7 Ms (e) 15.7 kg (f) 1.34 mm, 1.84 m

Step by step solution

01

Finding SI prefix for (a)

For (a), we have \(2.3 \times 10^{-10} L\). The exponent is -10, which corresponds to the SI prefix "pico" (p, \(10^{-12}\)). Therefore, we can rewrite this as 230 pL.
02

Finding SI prefix for (b)

For (b), we have \(4.7 \times 10^{-6} g\). The exponent is -6, which corresponds to the SI prefix "micro" (µ, \(10^{-6}\)). Therefore, we can rewrite this as 4.7 µg.
03

Finding SI prefix for (c)

For (c), we have \(1.85 \times 10^{-12} m\). The exponent is -12, which corresponds to the SI prefix "pico" (p, \(10^{-12}\)). Therefore, we can rewrite this as 1.85 pm.
04

Finding SI prefix for (d)

For (d), we have \(16.7 \times 10^{6} s\). The exponent is 6, which corresponds to the SI prefix "mega" (M, \(10^6\)). Therefore, we can rewrite this as 16.7 Ms.
05

Finding SI prefix for (e)

For (e), we have \(15.7 \times 10^{3} g\). The exponent is 3, which corresponds to the SI prefix "kilo" (k, \(10^3\)). Therefore, we can rewrite this as 15.7 kg.
06

Finding SI prefix for (f)

For (f), we have two quantities: \(1.34 \times 10^{-3} m\) and \(1.84 \times 10^{2} cm\). For the first quantity, the exponent is -3, which corresponds to the SI prefix "milli" (m, \(10^{-3}\)). Therefore, we can rewrite this as 1.34 mm. For the second quantity, note the unit is cm, and the exponent is 2, which corresponds to the SI prefix "hecto" (h, \(10^2\)). To stay in the base unit of meters, we convert 1 cm in meters first, which is equal to \(1 \times 10^{-2} m\). Then, we can rewrite this as \( 1.84 \times 10^{2} \times 10^{-2} m = 1.84 m\). Final answers: (a) 230 pL (b) 4.7 µg (c) 1.85 pm (d) 16.7 Ms (e) 15.7 kg (f) 1.34 mm, 1.84 m

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