Carry out the following conversions: (a) 0.105 in. to \(\mathrm{mm},\) (b) 0.650 qt to \(\mathrm{mL},\) (c) \(8.75 \mu \mathrm{m} / \mathrm{s}\) to \(\mathrm{km} / \mathrm{hr}\), (d) \(1.955 \mathrm{~m}^{3}\) to \(\mathrm{yd}^{3}\), (e) $$\$ 3.99 / \mathrm{lb}$$ to dollars per \(\mathrm{kg}\), (f) \(8.75 \mathrm{lb} / \mathrm{ft}^{3}\) to \(\mathrm{g} / \mathrm{mL}\)

Short Answer

Expert verified
The short answer for each conversion is as follows: (a) 0.105 in. = 2.667 mm (b) 0.650 qt = 615.13 mL (c) 8.75 μm/s = 0.0000275 km/hr (d) 1.955 m³ = 2.257 yd³ (e) $3.99/lb = $8.80/kg (f) 8.75 lb/ft³ = 0.139 g/mL

Step by step solution

01

(a) 0.105 in. to mm

Conversion factor: 1 in. = 25.4 mm 0.105 in. x 25.4 mm = 2.667 mm
02

(b) 0.650 qt to mL

Conversion factor: 1 qt = 946.353 mL 0.650 qt x 946.353 mL = 615.13 mL
03

(c) 8.75 μm/s to km/hr

Conversion factor: 1 μm = 1 x 10⁻⁶ km and 1 s = 1/3600 hr 8.75 μm/s x (1 x 10⁻⁶ km / 1 μm) x (1 hr / 3600 s) = 0.0000275 km/hr
04

(d) 1.955 m³ to yd³

Conversion factor: 1 m³ = 1.30795 yd³ 1.955 m³ x 1.30795 yd³ = 2.257 yd³
05

(e) $3.99/lb to dollars per kg

Conversion factor: 1 lb = 0.453592 kg (3.99 \(/lb) ÷ (0.453592 kg/lb) = 8.80 \)/kg
06

(f) 8.75 lb/ft³ to g/mL

Conversion factor: 1 lb = 453.592 g and 1 ft³ = 28316.8 mL (8.75 lb/ft³) x (453.592 g/lb) x (1 ft³ / 28316.8 mL) = 0.139 g/mL

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dimensional Analysis
Dimensional analysis is a mathematical technique widely used in science and engineering to convert one unit of measure to another. It's like a road trip where you map out your path using the specific directions and distances between points. In the classroom, it's an essential tool in understanding the relationship between different units and mastering unit conversions.

To carry out dimensional analysis, you start with the quantity you want to convert and multiply it by a series of conversion factors. These factors are fractions that represent the equality between units but are written in a form that allows canceling out the units you're converting from. It’s like exchanging currency when traveling abroad - you start with what you have and, using the exchange rate (a conversion factor), you end up with the currency you need.

For example, step 2 of the exercise given uses dimensional analysis to convert 0.650 quarts to milliliters. The solution uses the conversion factor that 1 quart is equivalent to 946.353 milliliters to navigate from quarts to milliliters.
Conversion Factors
Conversion factors are the exchange rates between units of measurement that you use during dimensional analysis. They allow you to convert quantities from one unit to another seamlessly. A conversion factor is created from any two quantities known to be equivalent. One key aspects when working with conversion factors is the principle of unity; it states that any number or quantity multiplied by one remains unchanged. Conversion factors are essentially a sophisticated form of the number one.

Imagine you're translating a book from one language to another. Each conversion factor is like a snippet of a bilingual dictionary that tells you exactly how a unit in one language translates to a unit in another language without changing the meaning - or in this case, the value. In our exercises, each step includes a specific conversion factor to translate the units correctly. For instance, to convert dollars per pound to dollars per kilogram, step 5 utilizes the conversion factor that 1 pound is equivalent to about 0.453592 kilograms.
Metric Conversion
Metric conversion involves changing measurements within the metric system or to different systems of measurement, like the imperial system used in the United States. The metric system is a decimal-based system of measurement, which makes it very straightforward to move between units - just like adding zeroes or moving decimal points.

Analogous to resizing photos for different platforms, where the image is still the same but fits into various contexts, metric conversions reshape measurements into new units without altering the quantity. For example, converting micrograms per second to kilometers per hour, as in step 3, requires understanding both the metric unit prefixes (micro and kilo) and the time unit relationships (seconds and hours). It's this versatility and ease of use that makes metric conversions a fundamental skill in many fields, particularly science and engineering.

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Most popular questions from this chapter

(a) A sample of tetrachloroethylene, a liquid used in dry cleaning that is being phased out because of its potential to cause cancer, has a mass of \(40.55 \mathrm{~g}\) and a volume of \(25.0 \mathrm{~mL}\) at \(25^{\circ} \mathrm{C}\). What is its density at this temperature? Will tetrachloroethylene float on water? (Materials that are less dense than water will float.) (b) Carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) is a gas at room temperature and pressure. However, carbon dioxide can be put under pressure to become a "supercritical fluid" that is a much safer drycleaning agent than tetrachloroethylene. At a certain pressure, the density of supercritical \(\mathrm{CO}_{2}\) is \(0.469 \mathrm{~g} / \mathrm{cm}^{3} .\) What is the mass of a \(25.0-\mathrm{mL}\) sample of supercritical \(\mathrm{CO}_{2}\) at this pressure?

Classify each of the following as a pure substance or a mixture. If a mixture, indicate whether it is homogeneous or heterogeneous: (a) rice pudding, (b) seawater, (c) magnesium, (d) crushed ice.

Identify each of the following as measurements of length, area, volume, mass, density, time, or temperature: (a) \(25 \mathrm{ps}\), (c) \(77 \mathrm{~K},(\mathbf{d}) 100,000 \mathrm{~km}^{2},\) (b) \(374.2 \mathrm{mg}\) (e) \(1.06 \mu \mathrm{m},(\mathrm{f}) 16 \mathrm{nm}^{2}\) \((g)-78^{\circ} \mathrm{C}\) (h) \(2.56 \mathrm{~g} / \mathrm{cm}^{3}\), (i) \(28 \mathrm{~cm}^{3}\). [Section 1.4].

In the year 2007 , an estimated amount of 31 billion tons of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) was emitted worldwide due to fossil fuel combustion and cement production. Express this mass of \(\mathrm{CO}_{2}\) in grams without exponential notation, using an appropriate metric prefix.

(a) To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a \(45-\mathrm{mL}\) sample of the substance. She then measured the mass of the sample, finding that it weighed \(38.5 \mathrm{~g}\). She knew that the substance had to be either isopropyl alcohol (density \(0.785 \mathrm{~g} / \mathrm{mL})\) or toluene (density \(0.866 / \mathrm{mL}\) ). What are the calculated density and the probable identity of the substance? (b) An experiment requires \(45.0 \mathrm{~g}\) of ethylene glycol, a liquid whose density is \(1.114 \mathrm{~g} / \mathrm{mL}\). Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume of the liquid should he use? (c) A cubic piece of metal measures \(5.00 \mathrm{~cm}\) on each edge. If the metal is nickel, whose density is \(8.90 \mathrm{~g} / \mathrm{cm}^{3},\) what is the mass of the cube?

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