Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 10: Problem 24

Hurricane Wilma of 2005 is the most intense hurricane on record in the Atlantic basin, with a low-pressure reading of 882 mbar (millibars). Convert this reading into (a) atmospheres, (b) torr, and (c) inches of \(\mathrm{Hg}\).

Short Answer

Expert verified
The pressure of Hurricane Wilma (882 mbar) can be converted into: (a) approximately 0.8705 atmospheres, (b) approximately 661 torr, and (c) approximately 26.04 inches of \(\mathrm{Hg}\).

Step by step solution

01

(a) Conversion to atmospheres

To convert the pressure reading from mbar to atmospheres, we can use the following proportion: \(1 \ \ \mathrm{atm} \ = \ 1013.25 \ \ \mathrm{mbar}\) Thus, to convert the pressure of 882 mbar to atmospheres, we have the equation: \[\frac{1 \ \mathrm{atm}}{1013.25 \ \mathrm{mbar}} \ = \frac{x}{882 \ \mathrm{mbar}}\] Solve for x: \[ x = \frac{882 \ \mathrm{mbar}}{1013.25 \ \mathrm{mbar}} \times 1 \ \mathrm{atm} \] \[ x \approx 0.8705 \ \mathrm{atm} \]
02

(b) Conversion to torr

To convert the pressure reading from mbar to torr, we can use the following proportion: \(1 \ \ \mathrm{atm} \ = \ 760 \ \ \mathrm{torr}\) Thus, to convert the pressure of 882 mbar to torr, we can first convert it to atm as in (a) and then multiply by the conversion factor for torr: \[ 882 \ \mathrm{mbar} \times \frac {1 \ \mathrm{atm}}{1013.25 \ \mathrm{mbar}} \times \frac {760 \ \mathrm{torr}}{1 \ \mathrm{atm}} \ = x \ \mathrm{torr} \] \[ x \approx 661 \ \mathrm{torr} \]
03

(c) Conversion to inches of \(\mathrm{Hg}\)

To convert the pressure reading from mbar to inches of \(\mathrm{Hg}\), we can use the following proportion: \(1 \ \ \mathrm{atm} \ = \ 29.92 \ \ \mathrm{in\ of\ Hg}\) Thus, to convert the pressure of 882 mbar to inches of \(\mathrm{Hg}\), we can first convert it to atm as in (a) and then multiply by the conversion factor for inches of \(\mathrm{Hg}\): \[ 882 \ \mathrm{mbar} \times \frac {1 \ \mathrm{atm}}{1013.25 \ \mathrm{mbar}} \times \frac {29.92 \ \mathrm{in\ of\ Hg}}{1 \ \mathrm{atm}} \ = x \ \mathrm{in\ of\ Hg} \] \[ x \approx 26.04 \ \mathrm{in\ of\ Hg} \] So, the pressure of Hurricane Wilma is approximately: (a) 0.8705 atmospheres, (b) 661 torr, and (c) 26.04 inches of \(\mathrm{Hg}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A quantity of \(\mathrm{N}_{2}\) gas originally held at 5.25 atm pressure in a 1.00-L container at \(26^{\circ} \mathrm{C}\) is transferred to a 12.5-L container at \(20^{\circ} \mathrm{C}\). A quantity of \(\mathrm{O}_{2}\) gas originally at \(5.25 \mathrm{~atm}\) and \(26^{\circ} \mathrm{C}\) in a 5.00-L container is transferred to this same container. What is the total pressure in the new container?

What change or changes in the state of a gas bring about each of the following effects? (a) The number of impacts per unit time on a given container wall increases. (b) The average energy of impact of molecules with the wall of the container decreases. (c) The average distance between gas molecules increases. (d) The average speed of molecules in the gas mixture is increased.

Rank the following gases from least dense to most dense at 1.00 atm and \(298 \mathrm{~K}: \mathrm{SO}_{2}, \mathrm{HBr}, \mathrm{CO}_{2} .\) Explain.

Cyclopropane, a gas used with oxygen as a general anesthetic, is composed of \(85.7 \% \mathrm{C}\) and \(14.3 \% \mathrm{H}\) by mass. \((\mathrm{a})\) If \(1.56 \mathrm{~g}\) of cyclopropane has a volume of \(1.00 \mathrm{~L}\) at 0.984 atm and \(50.0^{\circ} \mathrm{C}\), what is the molecular formula of cyclopropane? (b) Judging from its molecular formula, would you expect cyclopropane to deviate more or less than Ar from ideal-gas behavior at moderately high pressures and room temperature? Explain. (c) Would cyclopropane effuse through a pinhole faster or more slowly than methane, \(\mathrm{CH}_{4} ?\)

Newton had an incorrect theory of gases in which he assumed that all gas molecules repel one another and the walls of their container. Thus, the molecules of a gas are statically and uniformly distributed, trying to get as far apart as possible from one another and the vessel walls. This repulsion gives rise to pressure. Explain why Charles's law argues for the kineticmolecular theory and against Newton's model.
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Chemistry Branches

Read Explanation

Inorganic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free