Calculate each of the following quantities for an ideal gas: (a) the volume of the gas, in liters, if \(1.50 \mathrm{~mol}\) has a pressure of 1.25 atm at a temperature of \(-6^{\circ} \mathrm{C} ;(\mathbf{b})\) the absolute temperature of the gas at which \(3.33 \times 10^{-3}\) mol occupies \(478 \mathrm{~mL}\) at 750 torr; \((\mathbf{c})\) the pressure, in atmospheres, if \(0.00245 \mathrm{~mol}\) occupies \(413 \mathrm{~mL}\) at \(138{ }^{\circ} \mathrm{C} ;(\mathbf{d})\) the quantity of gas, in moles, if \(126.5 \mathrm{~L}\) at \(54^{\circ} \mathrm{C}\) has a pressure of \(11.25 \mathrm{kPa}\).

Short Answer

Expert verified
In conclusion: a) The volume of the gas in problem a is about 41.18 L. b) The absolute temperature of the gas in problem b is about 174.18 K. c) The pressure of the gas in problem c is about 19.52 atm. d) The quantity of gas in problem d is about 0.662 moles.

Step by step solution

01

Calculate the volume of the gas#for problem a

In this problem, we are given the number of moles (n), pressure (P), and temperature (T), and we need to calculate the volume (V). The temperature is given in Celsius and has to be converted to Kelvin: -6°C + 273.15 = 267.15 K. Using the Ideal Gas Law formula: \[V = \frac{nRT}{P}\] \[V = \frac{1.5 \mathrm{~moles} \times 0.0821 \mathrm{~L \cdot atm \cdot mol^{-1} \cdot K^{-1}} \times 267.15 \mathrm{~K}}{1.25 \mathrm{~atm}}\] Now we can calculate the volume (V) of the gas in liters: \[V \approx 41.18 \mathrm{~L}\]
02

Calculate the absolute temperature of the gas#for problem b

In this problem, we are given the number of moles (n), volume (V), and pressure (P), and we need to calculate the temperature (T). The volume is given in milliliters and has to be converted to liters: 478 mL = 0.478 L. The pressure is given in torr and should be converted to atmospheres: 750 torr ÷ 760 = 0.9868 atm. Using the Ideal Gas Law formula: \[T = \frac{PV}{nR}\] \[T = \frac{0.9868 \mathrm{~atm} \times 0.478 \mathrm{~L}}{3.33 \times 10^{-3}\mathrm{~moles} \times 0.0821 \mathrm{~L \cdot atm \cdot mol^{-1} \cdot K^{-1}}}\] Now we can calculate the temperature (T) of the gas in Kelvin: \[T \approx 174.18 \mathrm{~K}\]
03

Calculate the pressure of the gas#for problem c

In this problem, we are given the number of moles (n), volume (V), and temperature (T), and we need to calculate the pressure (P). The temperature is given in Celsius and has to be converted to Kelvin: 138°C + 273.15 = 411.15 K. The volume is given in milliliters and has to be converted to liters: 413 mL = 0.413 L. Using the Ideal Gas Law formula: \[P = \frac{nRT}{V}\] \[P = \frac{0.00245 \mathrm{~moles} \times 0.0821 \mathrm{~L \cdot atm \cdot mol^{-1} \cdot K^{-1}} \times 411.15 \mathrm{~K}}{0.413 \mathrm{~L}}\] Now we can calculate the pressure (P) of the gas in atmospheres: \[P \approx 19.52 \mathrm{~atm}\]
04

Calculate the number of moles of the gas#for problem d

In this problem, we are given the pressure (P), volume (V), and temperature (T) and we need to calculate the number of moles (n). The pressure is given in Pa and has to be converted to atmospheres: 11.25 kPa × 0.01 = 0.1125 atm. The temperature is given in Celsius and has to be converted to Kelvin: 54°C + 273.15 = 327.15 K. Using the Ideal Gas Law formula: \[n = \frac{PV}{RT}\] \[n = \frac{0.1125 \mathrm{~atm} \times 126.5 \mathrm{~L}}{0.0821 \mathrm{~L \cdot atm \cdot mol^{-1} \cdot K^{-1}} \times 327.15 \mathrm{~K}}\] Now we can calculate the number of moles (n) of the gas: \[n \approx 0.662 \mathrm{~moles}\] In conclusion: a) The volume of the gas in problem a is about 41.18 L. b) The absolute temperature of the gas in problem b is about 174.18 K. c) The pressure of the gas in problem c is about 19.52 atm. d) The quantity of gas in problem d is about 0.662 moles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Volume
The molar volume of a substance is the volume that one mole of gas occupies under certain conditions of temperature and pressure. It is particularly significant when discussing ideal gases. According to the Ideal Gas Law, all ideal gases have the same molar volume at a given temperature and pressure, making it a universal property.

For example, at standard temperature and pressure (0°C and 1 atmosphere), one mole of any ideal gas occupies 22.4 liters, known as the standard molar volume. However, the molar volume can vary greatly with different conditions, which is why we must use the Ideal Gas Law equation to calculate it for different scenarios, such as solving for the volume in the given exercise.

The Ideal Gas Law formula, \(V = \frac{nRT}{P}\), shows that the volume (V) is directly proportional to the amount of substance (n) in moles and the absolute temperature (T), and inversely proportional to the pressure (P). Understanding how these variables influence the molar volume is key to mastering problems involving gases.
Absolute Temperature
Temperature is a fundamental parameter in the study of gases, and the absolute temperature scale, measured in Kelvins (K), lays the groundwork for gas laws. It starts at absolute zero, the theoretical lowest possible temperature, where all molecular motion ceases.

These temperatures cannot be negative, because Kelvins are an absolute measure of thermal energy. To convert Celsius to Kelvin, the equation, \(K = ^\circ{}C + 273.15\), is used. For instance, in solving for the absolute temperature in the exercise provided, we use Kelvin to ensure that the temperature values are scientifically reasonable.

Since the Ideal Gas Law equations depend on absolute temperature, it is crucial to convert any Celsius temperatures into Kelvins to achieve accurate results. This reflects the direct relationship between temperature and other properties of gases: pressure, volume, and the number of moles.
Gas Pressure
Gas pressure is the force exerted by gas molecules as they collide with the walls of their container. It is dependent on the number of gas molecules, their speed, and the size of the container. Gas pressure can be measured in various units such as atmospheres (atm), Pascals (Pa), and torr, among others.

Pressure is a crucial variable in the Ideal Gas Law equation and can fundamentally alter gas behavior. When measuring pressure, it is important to convert it to the appropriate units before performing calculations, as shown in the exercise where torr is converted to atmospheres and kilopascals to atmospheres.

Pressure is inversely proportional to volume, assuming the number of moles and temperature are constant. As demonstrated in the exercise, if you increase the pressure exerted on a fixed amount of gas, the volume decreases, a concept central to understanding gas laws.
Moles of Gas
In chemistry, the mole is a unit of measurement for the amount of substance. It is one of the seven base SI units and is defined as containing exactly \(6.022 \times 10^{23}\) entities (Avogadro's number). When the context is the Ideal Gas Law, 'moles of gas' refers to the number of actual gas particles, whether they are atoms or molecules, contained in a sample.

The number of moles of gas is symbolized by the variable 'n' in the Ideal Gas Law and is directly proportional to the volume and temperature, while being inversely proportional to the pressure. Understanding the quantity of gas and how to calculate it, as illustrated in the final part of the exercise, is crucial in stoichiometry and for predicting how gases will respond to changes in physical conditions.

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