In dichloromethane, \(\mathrm{CH}_{2} \mathrm{Cl}_{2}(\mu=1.60 \mathrm{D})\), the dispersion force contribution to the intermolecular attractive forces is about five times larger than the dipole-dipole contribution. Compared to \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\), would you expect the relative importance of the dipole-dipole contribution to increase or decrease (a) in dibromomethane \((\mu=1.43 \mathrm{D}),(\mathbf{b})\) in difluoromethane \((\mu=1.93 \mathrm{D}) ?\) Explain.

Short Answer

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In conclusion, the relative importance of the dipole-dipole contribution to intermolecular attractive forces: (a) decreases for dibromomethane (\(\mathrm{CH}_{2}\mathrm{Br}_{2}\)) compared to dichloromethane (\(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)) (b) increases for difluoromethane (\(\mathrm{CH}_{2}\mathrm{F}_{2}\)) compared to dichloromethane (\(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)).

Step by step solution

01

Dispersion Force and Dipole-Dipole Force Ratio for CH2Cl2

First, let's analyze the given values for CH2Cl2 to understand the question's context. We are given that the dispersion force contribution is about five times larger than the dipole-dipole contribution for dichloromethane (CH2Cl2). Thus, the ratio of dispersion force to dipole-dipole force for CH2Cl2 is: Dispersion Force / Dipole-Dipole Force = 5 Keep this in mind as we continue to analyze the other two compounds.
02

Analyzing the Dipole Moment for CH2Br2 and CH2F2

We are given the dipole moments for dibromomethane (CH2Br2) and difluoromethane (CH2F2) as 1.43 D and 1.93 D, respectively. Dipole moment for CH2Br2: \(\mu = 1.43 \,\mathrm{D}\) Dipole moment for CH2F2: \(\mu = 1.93 \,\mathrm{D}\) Higher dipole moments typically correlate with stronger dipole-dipole interactions. To determine which compound has a larger relative importance of the dipole-dipole contribution, we need to compare the ratios of the dispersion forces to the dipole-dipole contributions for each compound.
03

Comparing the Dispersion Force to Dipole-Dipole Force Ratios

Let's analyze the dipole-dipole contribution of each compound in comparison to CH2Cl2. For CH2Br2: We can see that the dipole moment of CH2Br2 (1.43 D) is slightly lower than that of CH2Cl2 (1.60 D), which indicates that the strength of the dipole-dipole force contribution for CH2Br2 is expected to be weaker. As a result, it is likely that the dispersion force to dipole-dipole force ratio would be higher (more significant dispersion force contribution) for CH2Br2. Thus, the relative importance of dipole-dipole contribution for CH2Br2 decreases. For CH2F2: The dipole moment of CH2F2 (1.93 D) is higher than that of CH2Cl2 (1.60 D), indicating that the strength of the dipole-dipole force contribution for CH2F2 is likely to be stronger. Thus, the dispersion force to dipole-dipole force ratio would be lower (less significant dispersion force contribution) for CH2F2. So, the relative importance of dipole-dipole contribution for CH2F2 increases.
04

Conclusion

In conclusion, the relative importance of the dipole-dipole contribution to intermolecular attractive forces: (a) decreases for dibromomethane (CH2Br2) compared to dichloromethane (CH2Cl2) (b) increases for difluoromethane (CH2F2) compared to dichloromethane (CH2Cl2)

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Most popular questions from this chapter

Which member in each pair has the stronger intermolecular dispersion forces: (a) \(\mathrm{Br}_{2}\) or \(\mathrm{O}_{2}\), (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH},(\mathrm{c}) \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\) or \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCl} ?\)

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